Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 16)
16.
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
Answer: Option
Explanation:
| Work done by X in 4 days = |  |
1 | x 4 |  |
= | 1 | . |
| 20 | 5 |
| Remaining work = | |
1 - | 1 | |
= | 4 | . |
| 5 | 5 |
| (X + Y)'s 1 day's work = | |
1 | + | 1 | |
= | 8 | = | 2 | . |
| 20 | 12 | 60 | 15 |
| Now, | 2 | work is done by X and Y in 1 day. |
| 15 |
| So, | 4 | work will be done by X and Y in | |
15 | x | 4 | |
= 6 days. |
| 5 | 2 | 5 |
Hence, total time taken = (6 + 4) days = 10 days.
Discussion:
68 comments Page 7 of 7.
Inba said:
7 years ago
How come 4/5?
Please explain.
Please explain.
Srikanth Chowdary said:
1 decade ago
Mitra please explain clearly.
Jyoti said:
1 decade ago
How y=1 /12 please explain?
Prasana said:
1 decade ago
Why we are adding plus 4?
Jjjjjjjjjj said:
1 decade ago
Please explain clealrly.
Kumutha said:
1 decade ago
Please discuss clearly.
Anwesh said:
1 decade ago
Harsha realy well done.
Zeeshan said:
1 decade ago
Well done harsha.
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