Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 16)
16.
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
Answer: Option
Explanation:
| Work done by X in 4 days = |  |
1 | x 4 |  |
= | 1 | . |
| 20 | 5 |
| Remaining work = | |
1 - | 1 | |
= | 4 | . |
| 5 | 5 |
| (X + Y)'s 1 day's work = | |
1 | + | 1 | |
= | 8 | = | 2 | . |
| 20 | 12 | 60 | 15 |
| Now, | 2 | work is done by X and Y in 1 day. |
| 15 |
| So, | 4 | work will be done by X and Y in | |
15 | x | 4 | |
= 6 days. |
| 5 | 2 | 5 |
Hence, total time taken = (6 + 4) days = 10 days.
Discussion:
68 comments Page 6 of 7.
Lakshit said:
7 years ago
@Shweta.
Can you please elaborate last line?
Can you please elaborate last line?
Shree said:
8 years ago
Clear and detailed explanation. Thank you.
Akhil said:
1 decade ago
Can anyone explain this problem clearly.
Nagaraising said:
2 decades ago
Please explain about remaining work?.
Sree said:
1 decade ago
How 6+4?y should we add. Please help.
Shehina.s.p said:
2 decades ago
Please explain how {15/2*4/5} comes?
(1)
Lydia said:
1 decade ago
Please explain the remaining work.
Shanaya said:
4 years ago
Can you please explain 4/5 * 15/2?
(2)
Shanmugam said:
9 years ago
(1-1/5) = 4/5? Please explain it.
(1)
Akil Prakash said:
7 years ago
Thank you @Inna Reddy Chilakala.
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