Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x  x = |
 |
4 x 20 |  |
| 5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 8 of 10.
Siddharth said:
1 decade ago
Thanks kamal you are right.
Aisha said:
1 decade ago
Sakshi is doing work with x efficiency.
Tanya is doing work with x+25% of x efficiency.
Sakshi = x work.
Tanya = x+25/100x+125x/100 = 5/4x work.
ATQ,
Sakshi is taking 20 days means x ----> 20 days.
5/4x ----> 20 x 4/5 = 16 days.
Tanya is doing work with x+25% of x efficiency.
Sakshi = x work.
Tanya = x+25/100x+125x/100 = 5/4x work.
ATQ,
Sakshi is taking 20 days means x ----> 20 days.
5/4x ----> 20 x 4/5 = 16 days.
Raghu said:
10 years ago
The answer is 15 let me tell you.
Tanya is 25% efficient than Sakshi.
If Sakshi do a work in 24 hours then Tanya will do in 18 hours because 12 is 50% of 24. 6 is 25% of 24.
So Tanya take 6 hours less time than Sakshi, so reduce 6 hours in every day upto 20 days 6 x 20 = 120 i.e 5 days.
20 days - 5 days = 15 days.
Tanya is 25% efficient than Sakshi.
If Sakshi do a work in 24 hours then Tanya will do in 18 hours because 12 is 50% of 24. 6 is 25% of 24.
So Tanya take 6 hours less time than Sakshi, so reduce 6 hours in every day upto 20 days 6 x 20 = 120 i.e 5 days.
20 days - 5 days = 15 days.
Devi prasad said:
10 years ago
Their is mixed view of this question but we got both the answer correctly.
Vamsi said:
1 decade ago
If Tanya is 25% more efficient than Sakshi, then as 25% of 20 is 5. Tanya should complete the work in 15 days not 16 days.
Vijayalakshmi R said:
1 decade ago
S can do a work in 20 days so, s=1/20;
T can do a work 25% more efficient than S.
So, T = 1/20 + (25/100*1/20).
Finally we got T = 1/16.
So 16 is the correct answer.
I am sure about my answer so don't confuse, it may be 25 or other else.
T can do a work 25% more efficient than S.
So, T = 1/20 + (25/100*1/20).
Finally we got T = 1/16.
So 16 is the correct answer.
I am sure about my answer so don't confuse, it may be 25 or other else.
Sanjoy said:
1 decade ago
100T = 125S, 20S = 1, consider x day required for Tania.
4T = 5S, S = 1/20, Tx =1.
4T = 5*1/20 1/16x = 1.
4T = 1/4 x = 16.
T = 1/16.
So Tania required 16days to complete the work.
4T = 5S, S = 1/20, Tx =1.
4T = 5*1/20 1/16x = 1.
4T = 1/4 x = 16.
T = 1/16.
So Tania required 16days to complete the work.
Jitendra said:
1 decade ago
Why we should consider 125 and 100.
If we consider that Sakshi 100 and Tanya 75 then,
100 : 75 :: 20 : x.
= 100/75 = 20/x.
=> x = 15 days.
If we consider that Sakshi 100 and Tanya 75 then,
100 : 75 :: 20 : x.
= 100/75 = 20/x.
=> x = 15 days.
Jitendra said:
1 decade ago
Let Sakshi completes the whole work = 100 days.
Then Tanya will complete it = 75 days.
Now, 100 = 20.
1 = 20/100 = 1/5.
75 = (1/5) *75 = 15 days.
So answer should be 15 days.
Then Tanya will complete it = 75 days.
Now, 100 = 20.
1 = 20/100 = 1/5.
75 = (1/5) *75 = 15 days.
So answer should be 15 days.
Priya said:
1 decade ago
Nothing to do all this just simple calculation in question it is given Tanya is 25% more efficient than Sakshi which do in 20 days.
So Tanya will do 125/100*1/20 = 4 days.
So Tanya will do 125/100*1/20 = 4 days.
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