Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x  x = |
 |
4 x 20 |  |
| 5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 10 of 10.
Iqbal sofi said:
1 decade ago
It should be 15, because the 25% reduction of 20 is 15.
Shravani said:
1 decade ago
If tanya is 25% more efficient than sakshi (which means tanya>sakshi) then how cum the ratio between sakshi n tanya is 125:100 it should be 100:125 right?.
Sandeep said:
1 decade ago
(1/20 + 25% of 1/20).
Here 25 % of 1/20 is 1/5.
Then add,
(1/20+1/5), we get,
(1+4/20).
Then we get 1/4.
Above we got 4 days, then subtract 20 from 4
20-4 = 16.
Here 25 % of 1/20 is 1/5.
Then add,
(1/20+1/5), we get,
(1+4/20).
Then we get 1/4.
Above we got 4 days, then subtract 20 from 4
20-4 = 16.
Sai said:
1 decade ago
Tanya's one day work =(1/20 + 25% of 1/20) = 1/20+1/80 = 1/16 once explain the equation.
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