Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x ![]() |
![]() |
4 x 20 | ![]() |
5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 8 of 10.
Dhiman saab said:
1 decade ago
@Chandu.
It means 5:4 is known 125:100.
:: may mean equal to
20 here is the number of days taken by Sakshi and we are supposing x to be the days taken by Tanya.
It means 5:4 is known 125:100.
:: may mean equal to
20 here is the number of days taken by Sakshi and we are supposing x to be the days taken by Tanya.
Roji said:
1 decade ago
Hi friends,
Why can't we do in this manner?
Sakshi can done in 20 days i.e.,100%.
Where as, Tanya is x days i.e., 125%.
By cross multiplication,
x = (125*20)/100 = 25.
Answer we get 25.
So, am I wrong?
Already this type of process done in 17th sum but here it is not working yar.
Why can't we do in this manner?
Sakshi can done in 20 days i.e.,100%.
Where as, Tanya is x days i.e., 125%.
By cross multiplication,
x = (125*20)/100 = 25.
Answer we get 25.
So, am I wrong?
Already this type of process done in 17th sum but here it is not working yar.
San said:
1 decade ago
Efficiency is : (1/Number of total days to complete a work).
So, efficiency of sakshy = 1/20.
And,efficiency of Tanya = 1/20 + 25% of (1/20).
Which is,
1/16.
So, Tanya will complete in 16 days.
So, efficiency of sakshy = 1/20.
And,efficiency of Tanya = 1/20 + 25% of (1/20).
Which is,
1/16.
So, Tanya will complete in 16 days.
Soumil said:
1 decade ago
The ratio should be 100:75::20:x, not 125:100::20:x.
Pankaj said:
1 decade ago
I too get the answer as 15 days. Since 25% of 20 is 5 we have to subtract like 20-5 = 15 right? but how the answer is 16?
Akram said:
1 decade ago
x:y::p:q.
Product of mean = product of extreme.
..i.e.. y*p = x*q.
y*p/x*q = 1.
Same way : 5:4::20:x
4*20/5 = x
4*4 = x
x = 16.
Product of mean = product of extreme.
..i.e.. y*p = x*q.
y*p/x*q = 1.
Same way : 5:4::20:x
4*20/5 = x
4*4 = x
x = 16.
K verma said:
1 decade ago
Tanya is 25% more efficient than Sakshi.
Tanya is 125.
Sakshi is 100.
Ratio of efficiency is 5:4.
So, ratio of time will be 4:5.
Given, Sakshi can do work in 20 days means 5*4=20.
In the same way for Tanya 4*4=16.
Answer-16 days.
Tanya is 125.
Sakshi is 100.
Ratio of efficiency is 5:4.
So, ratio of time will be 4:5.
Given, Sakshi can do work in 20 days means 5*4=20.
In the same way for Tanya 4*4=16.
Answer-16 days.
Eby said:
1 decade ago
Tanya =125% of Sakshi
Sakshi 1 day work =1/20
So
Tanya =(125/100)*(1/20)
=(5/4)*(1/20)
=(1/4)*(1/4)
=(1/16)
=16 days
Sakshi 1 day work =1/20
So
Tanya =(125/100)*(1/20)
=(5/4)*(1/20)
=(1/4)*(1/4)
=(1/16)
=16 days
Pandian said:
1 decade ago
Sakshi done a work in 20 days is 100%
Tanya more power is 25%
So she done work in minimum days
So 25% of 20 days is 4
So tanya done work in 20-4 = 16 days.
Tanya more power is 25%
So she done work in minimum days
So 25% of 20 days is 4
So tanya done work in 20-4 = 16 days.
Shawisk said:
1 decade ago
Read carefully
for tanya & sakshi, the actual ratio is 100:75=4:3
bcz if tanya do same work complete @ 100% in x days
then sakshi can complete only 75% of that work in x days
so keep it in mind
for tanya & sakshi, the actual ratio is 100:75=4:3
bcz if tanya do same work complete @ 100% in x days
then sakshi can complete only 75% of that work in x days
so keep it in mind
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