Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x  x = |
 |
4 x 20 |  |
| 5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 10 of 10.
Sujith said:
1 decade ago
Tanya is 25% more efficient than Sakshi. Then ratio should be 3:4 rite ?.
Sandeep said:
1 decade ago
If tanya is 25% more efficient than sakshi (whic means tanya>sakshi) then how cum the ratio between sakshi n tanya is 125:100 it should be 100:125 right?.
Siddharth said:
1 decade ago
Thanks kamal you are right.
Kamlesh jaiswal said:
1 decade ago
The given answer is correct.
Sakshi's one day work=1/20
Tanya's one day work =(1/20 + 25% of 1/20) = 1/20+1/80 = 1/16.
So Tanya can complete the work in 16 days.
Sakshi's one day work=1/20
Tanya's one day work =(1/20 + 25% of 1/20) = 1/20+1/80 = 1/16.
So Tanya can complete the work in 16 days.
(1)
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