Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
15
16
18
25
Answer: Option
Explanation:

Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.

Suppose Tanya takes x days to do the work.

5 : 4 :: 20 : x    x = 4 x 20
5

x = 16 days.

Hence, Tanya takes 16 days to complete the work.

Discussion:
94 comments Page 7 of 10.

Jasmin said:   1 decade ago
Can you explain me chain rule please?

5:4 :: 20:x.

Geetha said:   1 decade ago
Give a brief explain how 125:100 come?

Anshu said:   1 decade ago
Hey,

You can understand it like this.
As we know working efficiency of sakshi is 1/20.
And working efficiency of tanya is 25% greater.

So tanya eff = 1/20*(125/100)=1/16.

Hence time 16 days.

Pavan said:   1 decade ago
Here question starts with sakshi so we must take s=100.

Then 25% eff so T=75.
Then the ratio we get is 3:4.

Answer will be 15.
How can it be 16.

Can anyone please?

Manjula said:   1 decade ago
Sakshi working days in 20 days means 100%.
Tanya working days ?

100%-75% = 25%

So 20*25/125 = 4.
20 days - 4 = 16 days.

Iqbal sofi said:   1 decade ago
It should be 15, because the 25% reduction of 20 is 15.

Ramesh said:   1 decade ago
Sakshi's one day work is 1/20.
Tanya is 25% of sakshi it means 1/20+25%1/20.

= (1/20+25/100*1/20).
= (1/20+1/80).
= 1/16 for one day.

So 16 days to do total work.

Shravani said:   1 decade ago
If tanya is 25% more efficient than sakshi (which means tanya>sakshi) then how cum the ratio between sakshi n tanya is 125:100 it should be 100:125 right?.

Sandeep said:   1 decade ago
(1/20 + 25% of 1/20).
Here 25 % of 1/20 is 1/5.

Then add,
(1/20+1/5), we get,
(1+4/20).

Then we get 1/4.

Above we got 4 days, then subtract 20 from 4
20-4 = 16.

Sai said:   1 decade ago
Tanya's one day work =(1/20 + 25% of 1/20) = 1/20+1/80 = 1/16 once explain the equation.


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