Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x ![]() |
![]() |
4 x 20 | ![]() |
5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 2 of 10.
Jothikumar said:
7 months ago
Sakshi = 120% of 20 days.
Tanya = 100% of x days.
X= 20*100/120,
X= 20*4/5.
X=80/4.
X= 16 days.
Tanya = 100% of x days.
X= 20*100/120,
X= 20*4/5.
X=80/4.
X= 16 days.
(3)
Batscy said:
5 years ago
Tanaya is - 25% more efficient than of (Sakshi).
So let's assume,
Sakshi takes 20 days to travel 2000km with a speed of 100km/ day
So Tania should take, X days to travel 2000km with the speed of 125% of (100km/day)
So speed should be, 100/100 * 25.
So time would be, 2000/125 = 16 days.
So let's assume,
Sakshi takes 20 days to travel 2000km with a speed of 100km/ day
So Tania should take, X days to travel 2000km with the speed of 125% of (100km/day)
So speed should be, 100/100 * 25.
So time would be, 2000/125 = 16 days.
(2)
Deepak khandagale said:
8 months ago
Sakshi completed the task in 20.
Tanya is 25% more efficient than Sakshi,
So 20/25= 0.8,
0.8 * 20 = 16,
So, Tanya takes 16 days to complete the whole task.
Tanya is 25% more efficient than Sakshi,
So 20/25= 0.8,
0.8 * 20 = 16,
So, Tanya takes 16 days to complete the whole task.
(2)
Vishal Bhadikar said:
7 years ago
Why not 15 days? Explain..
100%=20 day.
25%=x day.
X = 5 days.
Now take efficient that we need to subtract 20-5 = 15 days.
Explain to me if I am wrong.
100%=20 day.
25%=x day.
X = 5 days.
Now take efficient that we need to subtract 20-5 = 15 days.
Explain to me if I am wrong.
(2)
Ahsan Naveed said:
7 years ago
@All.
Tania is 25% more efficient then Sakshi so we can do it like,
Tania=125 units/day, Sakhi = 100 units/day.
As Sakhi done it in 20 days so we can find complete work done,
Total work= 20 * 100 = 2000.
We also have Tania unit work so we will divide total work with Tania unit work,
Tania work= 2000/125 = 16 answer.
Tania is 25% more efficient then Sakshi so we can do it like,
Tania=125 units/day, Sakhi = 100 units/day.
As Sakhi done it in 20 days so we can find complete work done,
Total work= 20 * 100 = 2000.
We also have Tania unit work so we will divide total work with Tania unit work,
Tania work= 2000/125 = 16 answer.
(2)
Manish Niroti said:
8 years ago
Tanya & sakshi capacity =5:4.
Tanya & Sakshi time taken=4:5.
If Sakshi taking 20 days it means 5 is representing 20 so 20/5 =4,
and multiply 4 with taken by Tanya so you will get 4*4 =16.
Ratio and proportion concept.
Tanya & Sakshi time taken=4:5.
If Sakshi taking 20 days it means 5 is representing 20 so 20/5 =4,
and multiply 4 with taken by Tanya so you will get 4*4 =16.
Ratio and proportion concept.
(1)
Kamlesh jaiswal said:
1 decade ago
The given answer is correct.
Sakshi's one day work=1/20
Tanya's one day work =(1/20 + 25% of 1/20) = 1/20+1/80 = 1/16.
So Tanya can complete the work in 16 days.
Sakshi's one day work=1/20
Tanya's one day work =(1/20 + 25% of 1/20) = 1/20+1/80 = 1/16.
So Tanya can complete the work in 16 days.
(1)
Annie said:
6 years ago
Can anyone please compare it with the 17th question?
(1)
Leela said:
6 years ago
@Ashan Naveed.
Consider 100 unit by Sakshi
Tanya 125 unit. Y can't we consider Sakshi by 125 days. Tanya in 100 days. Mainly unitary method how can we solve.
Consider 100 unit by Sakshi
Tanya 125 unit. Y can't we consider Sakshi by 125 days. Tanya in 100 days. Mainly unitary method how can we solve.
(1)
Tathagata said:
9 years ago
@Ashwini you are right. If you see a previous sum. If you do it in the same way it will have the same answer!
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