Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 8)
8.
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
Answer: Option
Explanation:
| (A + B)'s 1 day's work = | 1 |
| 10 |
| C's 1 day's work = | 1 |
| 50 |
| (A + B + C)'s 1 day's work = |  |
1 | + | 1 |  |
= | 6 | = | 3 | . .... (i) |
| 10 | 50 | 50 | 25 |
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
| From (i) and (ii), we get: 2 x (A's 1 day's work) = | 3 |
| 25 |
 A's 1 day's work = |
3 | . |
| 50 |
 B's 1 day's work |
|
1 | - | 3 | |
= | 2 | = | 1 | . |
| 10 | 50 | 50 | 25 |
So, B alone could do the work in 25 days.
Discussion:
147 comments Page 8 of 15.
Patil Pranay said:
1 year ago
A = B + C.
LCM of a+b and c =50,
Efficiency of A+B =5 c=1 than A+B+C=6.
A + B + C = 6 BUT A = B + C
A + A = 6
A = 3.
Then B = 2.
Ans = 50/2 = 25.
LCM of a+b and c =50,
Efficiency of A+B =5 c=1 than A+B+C=6.
A + B + C = 6 BUT A = B + C
A + A = 6
A = 3.
Then B = 2.
Ans = 50/2 = 25.
(55)
Priyanka said:
1 decade ago
A+B = 1/10.
C = 1/50.
A's time is equal to (B+C)'s time,
1/10-B = B+1/50.
2B = 1/10-1/50.
2B = 4/50.
B = 1/25.
B alone can do the work in 25 days.
C = 1/50.
A's time is equal to (B+C)'s time,
1/10-B = B+1/50.
2B = 1/10-1/50.
2B = 4/50.
B = 1/25.
B alone can do the work in 25 days.
Shruthi said:
1 decade ago
In general we get A+B+C=1/50,
But here we have A=B+C.
So, A+A=2A i.e 1/50*2 = 1/25
i.e B's 1 day work.
Finally B alone could do the work in 25 days.
But here we have A=B+C.
So, A+A=2A i.e 1/50*2 = 1/25
i.e B's 1 day work.
Finally B alone could do the work in 25 days.
Logunath said:
1 decade ago
We have....
A+B=1/10......(2)
A=B+C,
C=1/50,
We can set,
A-B=C
A-B=1/50......(1)
solving 1 and 2...
A=3/50,
so B=1/25,
B can do it in 25 day's.
A+B=1/10......(2)
A=B+C,
C=1/50,
We can set,
A-B=C
A-B=1/50......(1)
solving 1 and 2...
A=3/50,
so B=1/25,
B can do it in 25 day's.
Sarang said:
9 years ago
A = B + C.
A = B + 1/50.....(1)
A + B = 1/10.......(2)
PUT EQ (1) IN EQ (2). Then, Eq (2) becomes.
B + 1/50 + B = 1/10.
2B = 1/10 - 1/50.
B = 25.
A = B + 1/50.....(1)
A + B = 1/10.......(2)
PUT EQ (1) IN EQ (2). Then, Eq (2) becomes.
B + 1/50 + B = 1/10.
2B = 1/10 - 1/50.
B = 25.
Shivangini sharma said:
7 years ago
A = B+C.
A+B = 1/10.
Therefore
A = 1/10 - B.
1/10 - B = B + 1/50.
-B - B= 1/50 - 1/10,
= -2B = -4/50,
2B = 4/50,
100B = 4,
B = 4/100,
B = 1/25.
A+B = 1/10.
Therefore
A = 1/10 - B.
1/10 - B = B + 1/50.
-B - B= 1/50 - 1/10,
= -2B = -4/50,
2B = 4/50,
100B = 4,
B = 4/100,
B = 1/25.
Sathwik said:
9 years ago
A + B + C = 3/25.
A = B + C.
A = A + A.
A = 3/50.
A + B = 10.
=> 3/50 - 1/10 = 1/25.
Finally B = 25days.
A = B + C.
A = A + A.
A = 3/50.
A + B = 10.
=> 3/50 - 1/10 = 1/25.
Finally B = 25days.
Surinder kumar said:
7 years ago
a+b, +c can finished 50 work.
a+b finished in 5 days,
c finished in 1 day,
can say one day work (a+b+c) in 6 days,
a= b+c put,
a+(a) =6,
a=3.
a+b finished in 5 days,
c finished in 1 day,
can say one day work (a+b+c) in 6 days,
a= b+c put,
a+(a) =6,
a=3.
(1)
Ani said:
2 years ago
A = B+C,
A+B = 10,
C = 50.
A = B+C=> A = B+1/50.
A+B = 1/10 => B+1/50+B = 1/10.
2B + 1/50 = 1/10.
2B = 4/50.
B = 1/25.
25 DAYS.
A+B = 10,
C = 50.
A = B+C=> A = B+1/50.
A+B = 1/10 => B+1/50+B = 1/10.
2B + 1/50 = 1/10.
2B = 4/50.
B = 1/25.
25 DAYS.
(120)
Aunjani Kumar said:
1 decade ago
From (i) and (ii), we get: 2 x (A's 1 day's work) = 3/25
Dear i am not able to understand why 2 multiplied with A's day's work??????
Dear i am not able to understand why 2 multiplied with A's day's work??????
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