Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 8)
                   
                                       
                                8.
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
 
                                    Answer: Option
                                                    Explanation:
                                                
| (A + B)'s 1 day's work = | 1 | 
| 10 | 
| C's 1 day's work = | 1 | 
| 50 | 
| (A + B + C)'s 1 day's work = | ![]()  | 
    1 | + | 1 | ![]()  | 
    = | 6 | = | 3 | . .... (i) | 
| 10 | 50 | 50 | 25 | 
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
| From (i) and (ii), we get: 2 x (A's 1 day's work) = | 3 | 
| 25 | 
  A's 1 day's work = | 
    3 | . | 
| 50 | 
  B's 1 day's work | 
    ![]()  | 
    1 | - | 3 | ![]()  | 
    = | 2 | = | 1 | . | 
| 10 | 50 | 50 | 25 | 
So, B alone could do the work in 25 days.
Discussion:
147 comments Page 7 of 15.
                
                        Subhash said: 
                         
                        1 year ago
                
                A = B + C.
Lcm of 10 and 50 = 50 ( Total Work)
Eff of A + B = 5 --->1.
Eff of C = 1.
A = 5- B from 1.
A = B + C.
5 - B = B + 1.
B = 2.
Time= TW/Eff of B.
= 50/2 = 25.
                Lcm of 10 and 50 = 50 ( Total Work)
Eff of A + B = 5 --->1.
Eff of C = 1.
A = 5- B from 1.
A = B + C.
5 - B = B + 1.
B = 2.
Time= TW/Eff of B.
= 50/2 = 25.
                     (26)
                
            
                        Raghu said: 
                         
                        6 years ago
                
                A=B+C --- (1).
A+B=1/10 --- (2).
C=1/50 --- (3).
Substitute C in eq 1.
A=B+ (1/50).
From eq 2 we get A= (1/10) -B.
Substitute this in above eq.
(1/10)-B=B+ (1/50).
Solve it.
                A+B=1/10 --- (2).
C=1/50 --- (3).
Substitute C in eq 1.
A=B+ (1/50).
From eq 2 we get A= (1/10) -B.
Substitute this in above eq.
(1/10)-B=B+ (1/50).
Solve it.
                     (1)
                
            
                        Anonymous said: 
                         
                        9 years ago
                
                A = B + C.
A + B = 1/10.
A = 1/10 - B.
C = 1/50.
A = B + C.
1/10 - B = B + 1/50.
(1- 10B) /10= (50B + 1) /50.
50 - 500B = 500B + 10.
100B = 40.
B = 40/100.
B = 1/25.
B = 25.
                A + B = 1/10.
A = 1/10 - B.
C = 1/50.
A = B + C.
1/10 - B = B + 1/50.
(1- 10B) /10= (50B + 1) /50.
50 - 500B = 500B + 10.
100B = 40.
B = 40/100.
B = 1/25.
B = 25.
                        K Mohammad Rizwan said: 
                         
                        4 months ago
                
                1/A = 1/B + 1/ C  -->1
1/A + I/B = 1/10 -->2
1/C = 1/50 -->3
Subs 1 in 2.
1/B + 1/C + 1/B = 1/10 -->4
Subs 3 in 4.
2/B = 1/10 - 1/50.
2/B = 4/50,
B = 25.
                1/A + I/B = 1/10 -->2
1/C = 1/50 -->3
Subs 1 in 2.
1/B + 1/C + 1/B = 1/10 -->4
Subs 3 in 4.
2/B = 1/10 - 1/50.
2/B = 4/50,
B = 25.
                     (4)
                
            
                        Bunny said: 
                         
                        4 years ago
                
                They gave A = B+C, A+B = 10Days, C=50 Days;
A+B = 1/10;
since A = B+C;
B+C+B = 1/10;
2B+C = 1/10;
2B+1/50 = 1/10;
therefore B = 1/25;
B can complete in 25 days.
                A+B = 1/10;
since A = B+C;
B+C+B = 1/10;
2B+C = 1/10;
2B+1/50 = 1/10;
therefore B = 1/25;
B can complete in 25 days.
                     (14)
                
            
                        Mohanapriyadarshini said: 
                         
                        1 decade ago
                
                @awoke 
How come 2 b's ?
A + B = 1/10 but A = B + C, then
A + B = B + B + C = 1/10 and C = 1/50
a value is a+b ,what about b+c, why you are adding b+b+c ?
                How come 2 b's ?
A + B = 1/10 but A = B + C, then
A + B = B + B + C = 1/10 and C = 1/50
a value is a+b ,what about b+c, why you are adding b+b+c ?
                        PRAVEEN. P said: 
                         
                        8 years ago
                
                A+B=1/10.
C=1/50.
A+B+C=6/50.
But A=B+C.
B+C+B+C=6/50.
2B+2C=6/50.
But C=1/50.
On substitute c in above eqn we get as,
2B=4/50 and,
B=1/25,
Hence B=25 days.
                C=1/50.
A+B+C=6/50.
But A=B+C.
B+C+B+C=6/50.
2B+2C=6/50.
But C=1/50.
On substitute c in above eqn we get as,
2B=4/50 and,
B=1/25,
Hence B=25 days.
                        EKTA said: 
                         
                        1 decade ago
                
                1/A=1/B+1/C......I.
1/A+1/B=1/10...II.
1/C=1/50.....III.
PUT 1/A=1/B+1/C IN EQ II.
1/B+1/C+1/B=1/10
2/B+1/50=1/10
2/B=10-1/50
2/B=4/50
1/B=1/25
B=25.
                1/A+1/B=1/10...II.
1/C=1/50.....III.
PUT 1/A=1/B+1/C IN EQ II.
1/B+1/C+1/B=1/10
2/B+1/50=1/10
2/B=10-1/50
2/B=4/50
1/B=1/25
B=25.
                        Tenacious Guy said: 
                         
                        8 years ago
                
                It can also go like this, 
Since A=B+C.
So Add B on both sides you get.
A+B = 2B+C.
Solve it. 1/10 = 2B+1/50.
1/10 - 1/50.
4/50 = 2B.
B = 1/25.
25 Days.
                Since A=B+C.
So Add B on both sides you get.
A+B = 2B+C.
Solve it. 1/10 = 2B+1/50.
1/10 - 1/50.
4/50 = 2B.
B = 1/25.
25 Days.
                        Suresh said: 
                         
                        1 decade ago
                
                From given statement 
A+B+C = 6/50 ( A+B = 1/10 and C = 1/50)
Substitute A= B+C in above equation to get A= 3/50
3/50+B+1/50 = 6/50
B = 1/25
25 days
                A+B+C = 6/50 ( A+B = 1/10 and C = 1/50)
Substitute A= B+C in above equation to get A= 3/50
3/50+B+1/50 = 6/50
B = 1/25
25 days
Post your comments here:
 
            
        Quick links
                            Quantitative Aptitude
                                    
                                    Verbal (English)
                                    
                                    Reasoning
                                    
                                Programming
                                    
                                    Interview
                                    
                                     Placement Papers
                                    
                                

 A's 1 day's work =
 B's 1 day's work