Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 14)
14.
P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work?
Answer: Option
Explanation:
P can complete the work in (12 x 8) hrs. = 96 hrs.
Q can complete the work in (8 x 10) hrs. = 80 hrs.
 P's1 hour's work = |
1 | and Q's 1 hour's work = | 1 | . |
| 96 | 80 |
| (P + Q)'s 1 hour's work = |  |
1 | + | 1 |  |
= | 11 | . |
| 96 | 80 | 480 |
| So, both P and Q will finish the work in | |
480 | |
hrs. |
| 11 |
| Number of days of 8 hours each = |
|
480 | x | 1 | |
= | 60 | days = 5 | 5 | days. |
| 11 | 8 | 11 | 11 |
Discussion:
57 comments Page 2 of 6.
Jakrik said:
6 years ago
p to complete eating chocolate(12*8)=96hrs (work=chocolate).
q to complete eating chocolate(10*8)=80 hrs.
LCM of 96&80=480.
p->5 chocolates/hr(480/96).
Q->6 chocolates/hr(480/80).
In 1 hour = 5+6 = 11 chocolates.
8 hour =11 * 8 = 88(in one day)
Total chocolates = 480.
Days taken to complete = 480/88 = 60/11 = 5 5/11.
q to complete eating chocolate(10*8)=80 hrs.
LCM of 96&80=480.
p->5 chocolates/hr(480/96).
Q->6 chocolates/hr(480/80).
In 1 hour = 5+6 = 11 chocolates.
8 hour =11 * 8 = 88(in one day)
Total chocolates = 480.
Days taken to complete = 480/88 = 60/11 = 5 5/11.
(23)
Jitendra Gupta said:
1 decade ago
We can simply do the following!
Convert both the person's work into days bringing the same hours/day so the Man Days remain unchanged!!
Where P works 8 hour/Day working 12 Days= Man Days 96
Where Q works 8 hours / Day working 10 days= Man days 80
Now 1/10 + 1/12
So 11/60 per day work by both
so 60/11 = 5 5/11
Convert both the person's work into days bringing the same hours/day so the Man Days remain unchanged!!
Where P works 8 hour/Day working 12 Days= Man Days 96
Where Q works 8 hours / Day working 10 days= Man days 80
Now 1/10 + 1/12
So 11/60 per day work by both
so 60/11 = 5 5/11
Jaydeep Lalakiya said:
5 years ago
P = 12 days = 8 hours, hence P = 1/12 --> (i)
Q = 8 days = 10 hours.
So Q works 10 hours for 8 days so how many days he will take if he works for 8 hours only?
=8*10/8 = 10 days hence Q = 1/10--> (ii)
So now if both work together 1/12+1/10 = 11/60, (5 * 5/11 would be the answer).
Q = 8 days = 10 hours.
So Q works 10 hours for 8 days so how many days he will take if he works for 8 hours only?
=8*10/8 = 10 days hence Q = 1/10--> (ii)
So now if both work together 1/12+1/10 = 11/60, (5 * 5/11 would be the answer).
(5)
SrinivasaReddy said:
1 decade ago
P can do the work in 12days. He do per day 8 hours.
P can do work in total hours is:96.
Same as Q can do work in:80hours.
P's one day work is:1/96.
Q's one day work is:1/80.
P+q one day work is:1/96+1/80=11/480.
P+q work is:480/11.
P+q can done 8 hours per day:480/11*1/8.
P can do work in total hours is:96.
Same as Q can do work in:80hours.
P's one day work is:1/96.
Q's one day work is:1/80.
P+q one day work is:1/96+1/80=11/480.
P+q work is:480/11.
P+q can done 8 hours per day:480/11*1/8.
Dileep said:
1 decade ago
Given p can complete the work in 12 days working 8hrs a day.
i.e p - 12 days - 8 hrs.
lly, q - 8 days - 10 hrs (or) 10 days - 8 hrs.
Thus, p+q - x days - 8 hrs.
Hence p + q = 1/12 + 1/10.
= 22/120.
= 11/60.
Therefore p+q can complete the work in 60/11 days.
i.e p - 12 days - 8 hrs.
lly, q - 8 days - 10 hrs (or) 10 days - 8 hrs.
Thus, p+q - x days - 8 hrs.
Hence p + q = 1/12 + 1/10.
= 22/120.
= 11/60.
Therefore p+q can complete the work in 60/11 days.
Bhagyasri said:
8 years ago
1-hour work of p and q is(1/12*8+1/8*10) = 11/480.
8-hours of work is (11/480)*8 = 11/60.
For example, 1 day work is 1/x days then the total number of days is x.
Similarly, 8 hours of work is 11/60 then the total number of days is 60/11.
8-hours of work is (11/480)*8 = 11/60.
For example, 1 day work is 1/x days then the total number of days is x.
Similarly, 8 hours of work is 11/60 then the total number of days is 60/11.
Sush said:
1 decade ago
@Deeps
For 1hr-11/480th part of work is done.
So, to complete whole work it'll take 480/11hrs.
Eg:
For 1hr-1/4th f work
For xhr-1(whole) work..? x=4hrs.
Just take it to the l.h.s from r.h.s thats it.
Hope you are clear now...:)
For 1hr-11/480th part of work is done.
So, to complete whole work it'll take 480/11hrs.
Eg:
For 1hr-1/4th f work
For xhr-1(whole) work..? x=4hrs.
Just take it to the l.h.s from r.h.s thats it.
Hope you are clear now...:)
Deepak Patgar said:
1 decade ago
@Sumasree.
Suppose if A does a work in 8 days, amount of work done by him in 1 day will be 1/8,
Its the reciprocal.
In the same way if both of them does 11/60 work in 1 day they will require 60/11 days to complete that work.
Suppose if A does a work in 8 days, amount of work done by him in 1 day will be 1/8,
Its the reciprocal.
In the same way if both of them does 11/60 work in 1 day they will require 60/11 days to complete that work.
Nagu said:
2 decades ago
Hi all
we can write 60/11 = (5*11+5)/11
= (55+11)/11
it is same as 5 5/11 here first first 5 is quocient and senocd 5 is remainder and 11 is deviser
we can write 60/11 = (5*11+5)/11
= (55+11)/11
it is same as 5 5/11 here first first 5 is quocient and senocd 5 is remainder and 11 is deviser
Rajan said:
5 years ago
I want to know they work 8 hrs a day together, what it means they individual work for 8-8 hrs or their combined work is 8 hrs a day? Please, anyone, tell me.
(1)
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