Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 14)
14.
P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work?
Answer: Option
Explanation:
P can complete the work in (12 x 8) hrs. = 96 hrs.
Q can complete the work in (8 x 10) hrs. = 80 hrs.
![]() |
1 | and Q's 1 hour's work = | 1 | . |
96 | 80 |
(P + Q)'s 1 hour's work = | ![]() |
1 | + | 1 | ![]() |
= | 11 | . |
96 | 80 | 480 |
So, both P and Q will finish the work in | ![]() |
480 | ![]() |
hrs. |
11 |
![]() |
![]() |
480 | x | 1 | ![]() |
= | 60 | days = 5 | 5 | days. |
11 | 8 | 11 | 11 |
Discussion:
57 comments Page 1 of 6.
Hanmant said:
2 decades ago
How come 11/480?
Suresh said:
2 decades ago
How come 5 5/11 days from 60/11?
Deepak said:
2 decades ago
How come 11/480?
Manisha said:
2 decades ago
11/480 is the addition of 1/96+1/80
(1*5)/(96*5)+(1*6)/(80*6)=5/480+6/480=11/480
(1*5)/(96*5)+(1*6)/(80*6)=5/480+6/480=11/480
Asha said:
2 decades ago
When we divide 60 by 11 the quotient is 5 and the remainder is 5 11 is the divisor? so 5 5/11.
Nagu said:
2 decades ago
Hi all
we can write 60/11 = (5*11+5)/11
= (55+11)/11
it is same as 5 5/11 here first first 5 is quocient and senocd 5 is remainder and 11 is deviser
we can write 60/11 = (5*11+5)/11
= (55+11)/11
it is same as 5 5/11 here first first 5 is quocient and senocd 5 is remainder and 11 is deviser
Neha said:
1 decade ago
Why multiplied by (1/8)?
Rani Maria said:
1 decade ago
Take the LCM of 96,80 then we get 480.
then 1/96 * 480 + 1/80 *480 = 5/480 + 6/480 = 11/480.
then 1/96 * 480 + 1/80 *480 = 5/480 + 6/480 = 11/480.
Chintan said:
1 decade ago
Neha. . They work to gather 8 hours in 1 day that is shown in que. So ans mult. By 1/8
Supriya said:
1 decade ago
How can we solve this 480/11 * 1/8..and how came the ans 60/11 ?
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