Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 13)
13.
It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:
Answer: Option
Explanation:
Let the speed of the train be x km/hr and that of the car be y km/hr.
Then, | 120 | + | 480 | = 8 ![]() |
1 | + | 4 | = | 1 | ....(i) |
x | y | x | y | 15 |
And, | 200 | + | 400 | = | 25 | ![]() |
1 | + | 2 | = | 1 | ....(ii) |
x | y | 3 | x | y | 24 |
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.
Discussion:
84 comments Page 8 of 9.
Kishore said:
1 decade ago
Hello sir, how did come 1/15 at 1st step ?
Kavitha said:
1 decade ago
Hi manasa,
let the speed of the train be x kmph
let the speed of the car be y kmph
it is given that 120km is done by train,so D=120
by the formula D=S*T
T=120/X
and also given the rest is done by the car,
so D=600-120=480 km
T=480/y
then,120/x+480/y=8(read the question given problem clearly,in pbm it is given that to complete 600km journey,it will take 8hrs).
==>1/x+4/y=1/15...............eq1
similarly in case 2:
time for
train=200/x
car=400/y
and also given in pbm 20 min more so,
200/x+400/y=25/3(8hrs+20min=25/3)
==>1/x+2/y=1/24...............eq2
for solving these two equations as mathi said
then u will get 3:4
Hope u understand.
Bye
let the speed of the train be x kmph
let the speed of the car be y kmph
it is given that 120km is done by train,so D=120
by the formula D=S*T
T=120/X
and also given the rest is done by the car,
so D=600-120=480 km
T=480/y
then,120/x+480/y=8(read the question given problem clearly,in pbm it is given that to complete 600km journey,it will take 8hrs).
==>1/x+4/y=1/15...............eq1
similarly in case 2:
time for
train=200/x
car=400/y
and also given in pbm 20 min more so,
200/x+400/y=25/3(8hrs+20min=25/3)
==>1/x+2/y=1/24...............eq2
for solving these two equations as mathi said
then u will get 3:4
Hope u understand.
Bye
Manasa said:
1 decade ago
Please can any one help out this problem.
How they got 8 in first step?
How they got 8 in first step?
Mani said:
1 decade ago
Please can any one tell me how did you get the 1/24 in first step?
Sandy said:
1 decade ago
Please can any one tell me how did you get the 8 in first step?
Mathi said:
1 decade ago
Here to solve short cut method....
1/x+4/y=1/15 --> take xy as multiples
(y+4x)/xy=1/15 --> take 15 to left hand side
15y + 60x=xy
Similarly
1/x+2/y=1/24
24y+48x=xy
now easy to equate
15y+60x=24y+48x
60x-48x=24y-15y
12x=9y
x/y=9/12 --> x/y=3/4
hence 3:4
1/x+4/y=1/15 --> take xy as multiples
(y+4x)/xy=1/15 --> take 15 to left hand side
15y + 60x=xy
Similarly
1/x+2/y=1/24
24y+48x=xy
now easy to equate
15y+60x=24y+48x
60x-48x=24y-15y
12x=9y
x/y=9/12 --> x/y=3/4
hence 3:4
(1)
Hari said:
1 decade ago
Is there any short method for this?
(1)
Deepu said:
1 decade ago
By doing eqn(1) - eqn(2) we can get:
(4/y)-(2/y) = (1/15)-(1/24)
(4y-2y)/y2=(8-5)/120
2y/y2=3/120
2/y=1/40
y=80
By placing y value in eqn(1) we get x = 60.
(4/y)-(2/y) = (1/15)-(1/24)
(4y-2y)/y2=(8-5)/120
2y/y2=3/120
2/y=1/40
y=80
By placing y value in eqn(1) we get x = 60.
Bharatesh said:
1 decade ago
Please tell me how did you get the X value?
Shwetha said:
1 decade ago
Hi das 120 (1/x+4/y) = 8 then 1/x+4/y=8/20 that is equal to 1/x+4/y=1/15.
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