Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 13)
13.
It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:
2 : 3
3 : 2
3 : 4
4 : 3
Answer: Option
Explanation:

Let the speed of the train be x km/hr and that of the car be y km/hr.

Then, 120 + 480 = 8       1 + 4 = 1 ....(i)
x y x y 15

And, 200 + 400 = 25     1 + 2 = 1 ....(ii)
x y 3 x y 24

Solving (i) and (ii), we get: x = 60 and y = 80.

Ratio of speeds = 60 : 80 = 3 : 4.

Discussion:
84 comments Page 2 of 9.

Rahul Singh said:   8 years ago
Train covers 80Km more and car covers 80Km less, as a result 20min more is required. Suppose train covers 240Km(i.e. 3*80) more and car covers 240km(i.e. 3*80) less than it tooks 60min(i.e. 3*20) more.

Similarly, if train covers 480km more and car covers 480km less than time will increase by 120min i.e. 2hr. It means it the whole journey is covered by train only than it takes 10 hrs(8+2) to complete it. so speed of train = 600/10 = 60km/hr.

Now, time taken by train = 120/60 = 2 hrs.
So, time taken by car = 8 - 2 = 6 hrs.
And, speed of car = 480/6 = 80km/hr.
Speed of train : speed of car = 60:80 = 3:4.
(4)

Ayush said:   2 years ago
We got that,

Eq 1: 1/x+4/y=1/15 =>1/x=1/15-4/y.
Eq 2: 1/x+2/y=1/24 =>1/x=1/24-2/y.

Now equate the 1/x values.
i.e 1/15-4/y = 1/24-2/y =>2/y = 1/15-1/24.

So you get y = 80.
By submitting y in the eq 1: 1/x+4/80=1/15 and you get x =60.
X : Y = 60:80 =>3:4.
(4)

Karan K N said:   4 years ago
@Karan.

It's Given in the question;
Distance by train=200.
Remaining distance by car, So 600-200 = 400 is the distance covered by a car.
(3)

Vids said:   2 decades ago
Hi, from wher that 25/3 came?
(2)

Karan said:   4 years ago
How that 200 and 400 comes? Please explain me.
(2)

Soumitra said:   9 years ago
It takes more 20 min. It means 8hr + 20 min. Now convert into hr then it comes 20/60= 1/3. So time is 8hr+1/3hr= 25/3 hr.
(2)

Sai said:   7 years ago
How to find the x and y values can anyone help me?
(2)

Akanksha said:   5 years ago
I didn't understand the step of solving the equation 1 and 2. Please someone explain me.
(2)

Vikky said:   5 years ago
Hello.


Here we can solve the equation 1 & 2 by multiplying equation 1 & 2 by number 2.

i.e. multiply eq 1 with 2 it becomes,
2/x + 8/y = 2/15,
Now multiply eq 2 with 2 we get,
2/x + 4/y = 2/24.
Now, solving eq 1 & 2.
i.e. subtract eq 2 from eq 1 we, get,
Eq 1 - Eq 2.
2/x + 8/y = 2/15.
-( 2/x + 4/y ) = -2/24.
By cancellation and sloving we get:


4/y = 2/15 - 2/24.
By taking L.C.M we, get;

4/y = (8-5)/60,
4/y = 1/20.
i.e.. y= 80 then substitute the value of y in eq1 or eq 2 u will get the value of X as 60
Then their ratio is 3:4.
(2)

Abi said:   9 years ago
200/x + 400/y = 25/3.
200 (1/x + 2/y) = 25/3.

1/x + 2/y = 25/3 * 200 (multiply 3 * 200).
1/x + 2/y = 25/600.
1/x + 2/y = 1/24.

By solving this, we get 3 : 4.
(1)


Post your comments here:

Your comments will be displayed after verification.