Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
|
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
207 comments Page 7 of 21.
Sahil walia said:
8 years ago
Because converting 30 min into an hour because everything is given in hour so 30 min/60 to convert into hour so here it comes 1/2.
Yash said:
8 years ago
Hey guys!
Actually x=3/2 is the correct answer.
if new time = 1.5 hrs(i.e 3/2 hrs)
then original time=1.5-0.5(i.e 30 minutes)
=1 hr.
Then original speed = 600 kmph (since 600 km in an hr)
new speed = 600-200
= 400 kmph.
New time = 600/400
= 1.5 hrs (fits correctly with x=1.5 i.e our initial assumption).
Now,
x=1
original time =30 minutes= 0.5 hr
original speed = 600 kmph * 05 hr
= 1200 kmph
new speed = 1200-200
= 1000 kmph.
new time = 600/1000
= 36 minutes.
Since x=30 minutes; x is not equal new time.
so conclusion:- time =1.5 hrs (answer choices are incorrect).
Actually x=3/2 is the correct answer.
if new time = 1.5 hrs(i.e 3/2 hrs)
then original time=1.5-0.5(i.e 30 minutes)
=1 hr.
Then original speed = 600 kmph (since 600 km in an hr)
new speed = 600-200
= 400 kmph.
New time = 600/400
= 1.5 hrs (fits correctly with x=1.5 i.e our initial assumption).
Now,
x=1
original time =30 minutes= 0.5 hr
original speed = 600 kmph * 05 hr
= 1200 kmph
new speed = 1200-200
= 1000 kmph.
new time = 600/1000
= 36 minutes.
Since x=30 minutes; x is not equal new time.
so conclusion:- time =1.5 hrs (answer choices are incorrect).
Surya said:
8 years ago
S inversely proportional to time;
Time increases flight speed decreases
T1s1=T2S2
X*600=(x+30)400
6x=4x+120
X=60.
Time increases flight speed decreases
T1s1=T2S2
X*600=(x+30)400
6x=4x+120
X=60.
(1)
Madhava said:
8 years ago
How 600/x-600/x+1/2=200?
Why we take the difference and why it equal to 200?
Why we take the difference and why it equal to 200?
Madhav said:
8 years ago
How 600/x-600/x+2=200?
Please explain this step.
Please explain this step.
Madhav said:
8 years ago
Can anyone explain 1st step, I'm not understanding.
Chetna said:
8 years ago
30 min =1/2 hr.
Now I take time T in hr.
According to the question..... Distance is same so,
Distance of Normal flight = Distance due to bad weather (reduce by 200 kmph).
We know, distance = time * speed.
T*600 = ( 600-200) (T + 1/2) ..... (600-200 bcz speed is reduce by 200 kmph).
600T = 400T +200.
T= 1 hr.
Now I take time T in hr.
According to the question..... Distance is same so,
Distance of Normal flight = Distance due to bad weather (reduce by 200 kmph).
We know, distance = time * speed.
T*600 = ( 600-200) (T + 1/2) ..... (600-200 bcz speed is reduce by 200 kmph).
600T = 400T +200.
T= 1 hr.
Sneha said:
8 years ago
600(2x+1)-1200x=200x(2x+1).
1200x+600-1200x=400x^2+200x.
600=400x^2+200x,
300=200x^2+100,
3=2x^2+x,
2x^2+x-3=0.
1200x+600-1200x=400x^2+200x.
600=400x^2+200x,
300=200x^2+100,
3=2x^2+x,
2x^2+x-3=0.
Maulik Gajjar said:
8 years ago
Change in in speed i.e speed reduced by 200 kmph then change in time is 30 mnts.
If speed reduce to zero i.e by 600kmph. Time taken will be 90 mnts.
As mentioned in the question, Flight took 30 months more.
To find the original time of flight, 90 -30 = 60 months, i.e 1 hour.
If speed reduce to zero i.e by 600kmph. Time taken will be 90 mnts.
As mentioned in the question, Flight took 30 months more.
To find the original time of flight, 90 -30 = 60 months, i.e 1 hour.
Adil said:
8 years ago
Thanks @Kiran.
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