Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
1 hour
2 hours
3 hours
4 hours
Answer: Option
Explanation:

Let the duration of the flight be x hours.

Then, 600 - 600 = 200
x x + (1/2)

600 - 1200 = 200
x 2x + 1

x(2x + 1) = 3

2x2 + x - 3 = 0

(2x + 3)(x - 1) = 0

x = 1 hr.      [neglecting the -ve value of x]

Discussion:
206 comments Page 4 of 21.

Manish said:   5 years ago
Simple way to solve this problem:

Distance = speed * time.

Let the distance be d and the time taken by the plane at 600 km/hr be a
Then:

d=600*a (1) at regular speed
and, d=(600-200) * (a+.5 hr) (2) at reduced speed
Equating the two we get;

600*a = 400(a+.5)
600a = 400a + 200
200a=200
a=1.

The time taken is 1hr.
(5)

Aadarsh said:   5 years ago
@Diya.

Good explanation. Thanks.

Diya said:   5 years ago
Given distance =600.
Let initial speed and time be s & t.
So,speed s=600/t.

Now given speed is reduced by 200,so s becomes s-200 and time is increased by 30 mins, So t becomes t+(30/60) in hrs.
Distance= speed*time.
600=(s-200)(t+(30/60)).
Sub for s ,600=(600/t -200)(t+(30/60)).
600=200[(3/t)-1](3t/2).
1=(3/2)-(t/2).
t = 1.
(2)

Prabi said:   5 years ago
@Neeru.

1/2 is because here told that 30 minutes. If it is 60 minutes then it will be 1.

Neeru sharma said:   5 years ago
How come 1/2?
(1)

Parimalanathan said:   6 years ago
I can't understand this.
(1)

Sabur khan said:   6 years ago
It must be 1.5 hours.
(1)

Raman said:   6 years ago
Good. Thanks @Vijaya Laxmi.
(1)

Bhadru said:   6 years ago
Thank you @Muzzu.
(1)

Muzzu said:   6 years ago
T+30 = 600/400,
T+30/60 = 3/2,
T+1/2 = 3/2,
T= 3/2-1/2,
T= 1 hour.
(3)


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