Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
|
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
207 comments Page 21 of 21.
Meron said:
7 years ago
I am not getting this, please explain.
Anand Kumar said:
7 years ago
600/(x-200) - 30/60 =600/x ---> Eq.(1)
=> from equation (1) we get , x = 600.
Now, we have to find the duration of the flight = 600/x = 600/600 = 1hour. Answer.
=> from equation (1) we get , x = 600.
Now, we have to find the duration of the flight = 600/x = 600/600 = 1hour. Answer.
Prabi said:
6 years ago
@Neeru.
1/2 is because here told that 30 minutes. If it is 60 minutes then it will be 1.
1/2 is because here told that 30 minutes. If it is 60 minutes then it will be 1.
Aadarsh said:
5 years ago
@Diya.
Good explanation. Thanks.
Good explanation. Thanks.
Navin said:
4 years ago
@Saravanakgopi.
Thanks for simplifying the answer in detail.
Thanks for simplifying the answer in detail.
Tony said:
4 years ago
Anyone, please explain from the 2nd Step.
Yash Soni said:
4 years ago
Can we take the difference of time instead of speed? Please anyone explain me.
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