Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
1 hour
2 hours
3 hours
4 hours
Answer: Option
Explanation:

Let the duration of the flight be x hours.

Then, 600 - 600 = 200
x x + (1/2)

600 - 1200 = 200
x 2x + 1

x(2x + 1) = 3

2x2 + x - 3 = 0

(2x + 3)(x - 1) = 0

x = 1 hr.      [neglecting the -ve value of x]

Discussion:
206 comments Page 19 of 21.

Manasi said:   1 decade ago
Awesome @Saravanakgopi.

Thanks dude.

Anu said:   1 decade ago
@Saravanakgopi tell me how you get 5400 in your result.

Madhu said:   1 decade ago
Excellent saravanakgopi.

Pavan said:   1 decade ago
Helloo kiran I have 1 doubt you say that x is in hr so 3 you taken as x/2 but we dnt't know what is x value it may be 2hr 3hr. Then how you will take 3min=x/2.

Saravanakgopi said:   1 decade ago
Another method: We know
Speed = Distance covered/ time taken
speed = 200km/hr
Distance=600km
time=x+30 (30 min. increase)

Apply the formule:

200 =600/x+30
200(x+30)=600
200x =5400
x = 27 min.
Now Time = x+30 so 27+30= 57 Min. Approx 1 Hr.

Reeta said:   1 decade ago
600/x-1200/(2x+1) = 200
divide eq by 100,we get the eq.
6/x-12/(2x+1) = 2

Now its simple to solve

Hemant said:   1 decade ago
(2x+1)(600)-1200x=200(2x^2 +x)
2x^2 +x=3
explain

Chris said:   1 decade ago
Please can anyone tell me what is the LCM taken?

Karthik said:   1 decade ago
(600/x)-600/(x+1/2)=200

(600/x)-600*2/(2x+1)=200
take LCM we will get
(600(2x+1)-600*2*x)/x*(2x+1)=200

600(2x+1)-600*2*x=200*x*(2x+1)
600(2x+1)-200*x*(2x+1)=600*2*x

i think now it ll b easy to simply

Appu said:   1 decade ago
Can anybody solve (600/x)-600(x+1/2)=200?


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