Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
1 hour
2 hours
3 hours
4 hours
Answer: Option
Explanation:

Let the duration of the flight be x hours.

Then, 600 - 600 = 200
x x + (1/2)

600 - 1200 = 200
x 2x + 1

x(2x + 1) = 3

2x2 + x - 3 = 0

(2x + 3)(x - 1) = 0

x = 1 hr.      [neglecting the -ve value of x]

Discussion:
206 comments Page 17 of 21.

Kishor said:   7 years ago
Thank you @Bhavana and @Shanti.

Meron said:   7 years ago
I am not getting this, please explain.

Anand Kumar said:   7 years ago
600/(x-200) - 30/60 =600/x ---> Eq.(1)
=> from equation (1) we get , x = 600.

Now, we have to find the duration of the flight = 600/x = 600/600 = 1hour. Answer.

Sami said:   7 years ago
Speed = distance/time.
Time = distance/speed.
Speed=600-200 = 400 km/hr.
Distance to cover = 600 km.

Duration required(time) = 600/400 = 3/2 hr.
3/2*60 = 60 min = 1hr.
(4)

Esha said:   6 years ago
How do we get x(2x + 1) = 3? please explain.
(1)

Vijaya lakshmi said:   6 years ago
We know that speed = distance/time;

Let us assume time as x,then actual speed=600/x;
Now the time is incremented to 30 min right,

So, now the speed=600/(x+1/2)
Here we take the time in hrs so (x+1/2).

In the problem, the speed is reduced by 200km/hr
So the diff between speed is equal to 200km/hr.

i.e. 600/x-600/x+(1/2) = 200.
(3)

Muzzu said:   6 years ago
T+30 = 600/400,
T+30/60 = 3/2,
T+1/2 = 3/2,
T= 3/2-1/2,
T= 1 hour.
(3)

Bhadru said:   6 years ago
Thank you @Muzzu.
(1)

Raman said:   6 years ago
Good. Thanks @Vijaya Laxmi.
(1)

Sabur khan said:   6 years ago
It must be 1.5 hours.
(1)


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