Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
 |
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
210 comments Page 14 of 21.
Suchitra said:
1 decade ago
@Mallikarjun.
Why it can't be like?
400 km. > 30 min.
600 km. > ?
Why are you taking 200? 200 is the speed reduced?
So shouldn't you subtract from 600 and take it as 400.
Why it can't be like?
400 km. > 30 min.
600 km. > ?
Why are you taking 200? 200 is the speed reduced?
So shouldn't you subtract from 600 and take it as 400.
Arul said:
1 decade ago
Why 600/x-600/x+1/2 not 600/x+1/2-600/x?
Please clear the concept. I can't understand.
Please clear the concept. I can't understand.
Mangesh said:
1 decade ago
Please tell me in separate steps to solve this example.
Kavita said:
1 decade ago
How you take 1200/2x +1? If you get 1200 then how its possible 2x+1.
Hemant said:
1 decade ago
x-2x+2x+x/x+x+1, please solve this problem.
Hemant said:
1 decade ago
x-2x+2x+x/x+x+1, please solve this problem.
Shalz said:
1 decade ago
Hello friends.
Here D = 600 km.
Average speed = 200.
Here in the problem he did not mentioned about time so lets take it as x.
But he given increased time as 30 min.
So according to the problem actual time = x+30 min.
So, he is asking duration T=D/S.
x+30 = 600/200.
x+30 = 3.
x = 30-3 = 27 min.
But actual time = x+30 = 27+30 = 57 min approx 1 hr.
Here D = 600 km.
Average speed = 200.
Here in the problem he did not mentioned about time so lets take it as x.
But he given increased time as 30 min.
So according to the problem actual time = x+30 min.
So, he is asking duration T=D/S.
x+30 = 600/200.
x+30 = 3.
x = 30-3 = 27 min.
But actual time = x+30 = 27+30 = 57 min approx 1 hr.
Uday said:
1 decade ago
I have a quest actually the time is x+1/2 hours after delay that's the whole duration of flight but its taken as only x now its actually x+1/2 = 1 and half hour.
Manikanta said:
1 decade ago
I have a doubt in the question its average speed for the trip was reduced by 200 km/hr is given but trip means both up and down so that its 1200 kms but in the answer only 600 km is taken.
Manikanta said:
1 decade ago
In this question I have a doubt its average speed for the trip was reduced by 200 km/hr i.e., trip means both upside and downside distance. Such that the distance is 1200 km (600 km for upside and 600 km for downside).
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