Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
209 comments Page 8 of 21.
C.h.udhay said:
9 years ago
Abhay takes 2 times more than Sameer
2x = x.
If Sameer doubles his speed, he would take less than 1hour of Sameer
2 * 2x = 1 - x,
4x = 1 - x,
4x + x = 1,
5x = 1,
x = 1 ÷ 5.
According to question, speed is 1 ÷ 5 is 5.
2x = x.
If Sameer doubles his speed, he would take less than 1hour of Sameer
2 * 2x = 1 - x,
4x = 1 - x,
4x + x = 1,
5x = 1,
x = 1 ÷ 5.
According to question, speed is 1 ÷ 5 is 5.
Teja said:
9 years ago
Total = 30 km.
Speed = 1 : 2.
That is time = 2 : 1.
Difference between time is 1 = 3(3 get from question is more than 2 hrs and less than 1 hrs)
2 * 3 = 6;
Abhay speed =30/6 = 5 km/hrs.
Sameer speed = 30/4 = 7.5 km/hrs.
Speed = 1 : 2.
That is time = 2 : 1.
Difference between time is 1 = 3(3 get from question is more than 2 hrs and less than 1 hrs)
2 * 3 = 6;
Abhay speed =30/6 = 5 km/hrs.
Sameer speed = 30/4 = 7.5 km/hrs.
Kingstan said:
1 decade ago
Guys all are confusing ! here the simple method.
Ajay = x+2 (2 hours more than sameer?)
= 2(x-1) (doubles and 1 hour less?)
Therefore x=? 4? so sameer is 4 na ajay ? 6?
Then? s-d/t ? 30/6 --- 5 (ANS) !! Simple.
Ajay = x+2 (2 hours more than sameer?)
= 2(x-1) (doubles and 1 hour less?)
Therefore x=? 4? so sameer is 4 na ajay ? 6?
Then? s-d/t ? 30/6 --- 5 (ANS) !! Simple.
Ano said:
6 years ago
Take one option 5hrs if Abhay goes with 5km/hr then it will take 6 hours to reach means 4 hours for Sameer. If he doubles his speed means 30/10 = 3kmph and as usual Sameer speed is 4kmph so the right answer is A.
Tejeshwar Rao said:
8 years ago
Distance=30km.
Let the speeds of abhay be x kmph and sameer be y kmph.
Then,
30/x - 30/y =2 ---> I.
When abhay doubles his speed
30/y - 30/2x = 1 ---> II
By I + II we get,
30/x - 30/2x=3
6x=30.
x=5km/hr.
Let the speeds of abhay be x kmph and sameer be y kmph.
Then,
30/x - 30/y =2 ---> I.
When abhay doubles his speed
30/y - 30/2x = 1 ---> II
By I + II we get,
30/x - 30/2x=3
6x=30.
x=5km/hr.
Thiru.G said:
2 decades ago
If suppose x speet abay cover in y+2 time .
then 2x speed he covered in y-1.(here y is sameer to cover time).
then diirent between time = (y+2)-(y-1)=3.so
first covered time - second covered time = 3.
then 2x speed he covered in y-1.(here y is sameer to cover time).
then diirent between time = (y+2)-(y-1)=3.so
first covered time - second covered time = 3.
(2)
Abhi said:
1 decade ago
When Abhay doubled the speed he gained a total of 3 hours (he was 2 was behind but when doubled he gained 1 hour. ).
This means when he was in his actual speed he was taking 6 hours.
So 30/6 = 5 kmph.
This means when he was in his actual speed he was taking 6 hours.
So 30/6 = 5 kmph.
Tejeshwar Rao said:
8 years ago
Distance=30km.
Let the speeds of abhay be x kmph and sameer be y kmph.
then,
30/x - 30/y =2----i,
When abhay doubles his speed
30/y - 30/2x = 1-----ii,
By i+ii we get,
30/x - 30/2x=3,
6x=30,
x=5km/hr.
Let the speeds of abhay be x kmph and sameer be y kmph.
then,
30/x - 30/y =2----i,
When abhay doubles his speed
30/y - 30/2x = 1-----ii,
By i+ii we get,
30/x - 30/2x=3,
6x=30,
x=5km/hr.
Aditya said:
1 decade ago
@Abhi.
I still don't get it. The "3" from the original solution. He was supposed to be 2 hours behind. How does doubling his speed Which would means he takes 1 hour less than sameer end up being "3".
I still don't get it. The "3" from the original solution. He was supposed to be 2 hours behind. How does doubling his speed Which would means he takes 1 hour less than sameer end up being "3".
Meenakshi said:
4 years ago
Actually use simple logic.
Initially, he took 2 hrs more than Sameer, then he took one hr less.
which means the difference in time that has occurred in 3hrs.
So, Intial time - final time = 3hrs.
Initially, he took 2 hrs more than Sameer, then he took one hr less.
which means the difference in time that has occurred in 3hrs.
So, Intial time - final time = 3hrs.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers