Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
209 comments Page 8 of 21.
Archna said:
8 years ago
Let's speed of Abhay is x.
Then 30/x-30/2x=3,
30/x-15/x=3,
15/x=3,
X=15/3,
X=5 answer.
Then 30/x-30/2x=3,
30/x-15/x=3,
15/x=3,
X=15/3,
X=5 answer.
Shalu said:
8 years ago
Thank you @Devi.
Great explanation.
Great explanation.
Shree said:
8 years ago
Thank you @Devi.
Bahisht said:
8 years ago
Thank you @Devi.
Mohini mohanty said:
8 years ago
Thank you @Devi.
Sathya said:
8 years ago
Please explain in simple method.
Vignesh sk said:
8 years ago
Distance=30km/h0r.
time taken by Sameer is t,
Abhay travelling with a Speed X.
Case 1:
time taken by Abhay to cover 30km is 30/X = t+2.
Case 2(doubles speed):
time taken by Abhay to cover 30km is 30/2X = t-1.
(30/X)- (30/2X) = (t+2)-(t-1),
(30/X) - (30/2X) = t+2-t+1,
(30*2X) - (30*X) = 3 (2X^2) //LCM,
60X - 30X = 6 X^2,
30X = 6 X^2,
30 = 6 X,
X = 5.
time taken by Sameer is t,
Abhay travelling with a Speed X.
Case 1:
time taken by Abhay to cover 30km is 30/X = t+2.
Case 2(doubles speed):
time taken by Abhay to cover 30km is 30/2X = t-1.
(30/X)- (30/2X) = (t+2)-(t-1),
(30/X) - (30/2X) = t+2-t+1,
(30*2X) - (30*X) = 3 (2X^2) //LCM,
60X - 30X = 6 X^2,
30X = 6 X^2,
30 = 6 X,
X = 5.
DIPS said:
8 years ago
Case 1: Abhay's speed=x.
Abhays time =t+2,
velocity(x)=30/t+2,
Case 2: abhays speed=2x.
Abhays time =t-1,
velocity doubled 2x=30/t-1.
now substitute the value of x in case 2.
t=4 substitute this value in any of the equations above.
x=5 is the ans.
Abhays time =t+2,
velocity(x)=30/t+2,
Case 2: abhays speed=2x.
Abhays time =t-1,
velocity doubled 2x=30/t-1.
now substitute the value of x in case 2.
t=4 substitute this value in any of the equations above.
x=5 is the ans.
Chandru said:
8 years ago
30/x-30/2x=3.
2*30/2*x-30/2x=3.
60/2x-30/2x=3.
30/2x=3
30=3*2x
30=6x,
x=30/6,
x=5kmph.
2*30/2*x-30/2x=3.
60/2x-30/2x=3.
30/2x=3
30=3*2x
30=6x,
x=30/6,
x=5kmph.
Ankan Banerjee said:
8 years ago
Let time taken by Sameer = T hrs.
Before doubling speed, time taken by Abhay = T+2 hrs --> (1).
After doubling the speed time taken = T-1 hrs --> (2).
(1) - (2) = (T+2) - (T-1) = 3 hrs.
Before doubling speed, time taken by Abhay = T+2 hrs --> (1).
After doubling the speed time taken = T-1 hrs --> (2).
(1) - (2) = (T+2) - (T-1) = 3 hrs.
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