Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
5 kmph
6 kmph
6.25 kmph
7.5 kmph
Answer: Option
Explanation:

Let Abhay's speed be x km/hr.

Then, 30 - 30 = 3
x 2x

6x = 30

x = 5 km/hr.

Discussion:
209 comments Page 6 of 21.

Zabi said:   1 decade ago
Great explanation devi.

Anoo said:   1 decade ago
Time in first case= 30/x(30 is distance and x is speed)

Time in second case=30/2x(30 is distance and speed is doubled)

Total difference in time is 3 hrs(2 hrs slow and one hour fast)

(30/x)-(30/2x)=3

Solve and you get 5km/hr.

Rahul said:   1 decade ago
Let Abhay's speed be x km/hr
and sameer's speed be y km/hr

Abhay takes 2 hours more than Sameer
i.e (30/x)-(30/y)=2 ........ I

Abhay doubles his speed, i.e his speed becomes 2x
then he would take 1 hour less than Sameer

i.e (30/y)-(30/2x)=1......... II

ADD I and II
you will get

(30/x)-(30/2x)=3.......... III
solve III you will get x=5 km/h

Appu said:   1 decade ago
Nice explanation by Anoo.

Kamal said:   1 decade ago
Reason for substracting two equation is.?

Priya said:   1 decade ago
Reason for substracting?

Varun said:   1 decade ago
Reason for subtracting: Then only you're getting the difference in time of both.

Bhavana said:   1 decade ago
Good explanation by rahul and amith.

Srikara said:   1 decade ago
Good Explanation Devi.. Thanx.. :)

Harish said:   1 decade ago
thanks


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