Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
209 comments Page 20 of 21.
Vishnu Priya said:
1 decade ago
Thank you sakshi..
Prince said:
1 decade ago
30/x(1-1/2)=3
15x=3
x=5
15x=3
x=5
Sakshi said:
1 decade ago
Its a little bit long bt simple way to solve it.
Let suppose Sameer takes x hrs to cover distance
so, Abhay will take x+2 hrs
speed of Abhay = dis/time = 30/x+2
when Abhay doubles his speed = 2*30/x+2 = 60/x+2
now, time taking by Abhay = dis/speed = 30/60/x+2 = x+2/2..0k
Abhay wiil take 1 hr less than Sameer
Therrfore, x+2/2= x-1; x=4
Abhay's time= x+2= 6
now Abhay's speed= 30/6= 5km/hr.
Let suppose Sameer takes x hrs to cover distance
so, Abhay will take x+2 hrs
speed of Abhay = dis/time = 30/x+2
when Abhay doubles his speed = 2*30/x+2 = 60/x+2
now, time taking by Abhay = dis/speed = 30/60/x+2 = x+2/2..0k
Abhay wiil take 1 hr less than Sameer
Therrfore, x+2/2= x-1; x=4
Abhay's time= x+2= 6
now Abhay's speed= 30/6= 5km/hr.
Abdus samadh said:
1 decade ago
From devi's explanation, after 2nd line((30/X) - (30/2X) = t+2-t+1)
60/2X - 30/2X = 3;
30 = 6X(3 * 2X);
so X=5;
is it right?
60/2X - 30/2X = 3;
30 = 6X(3 * 2X);
so X=5;
is it right?
Kumr said:
1 decade ago
How equal to 3. More than sameer in 2 hours after less than sameer 1 hr why its came?
Pooja said:
1 decade ago
I am not able to understand
Shiva said:
1 decade ago
Thanks devi. Great explanation.
Ramya said:
1 decade ago
Thanks devi:).
Joti said:
1 decade ago
@thiru.g.
Thank you.
Thank you.
Noufal said:
1 decade ago
Thanx DEVI you are great.
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