Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
209 comments Page 13 of 21.
Latika said:
9 years ago
If the distance is same then,
Sameer's speed = 30/4.
= 7.5 km/hr.
Sameer's speed = 30/4.
= 7.5 km/hr.
Ritika said:
6 years ago
I don't understand why we subtract 30/x-30/2x? Please explain me.
Sarang said:
3 years ago
d = (s1*s2*time diff)/( s1-s2).
30 = x * 2x * 3/x * 2x.
x = 5.
30 = x * 2x * 3/x * 2x.
x = 5.
(7)
Keshav said:
10 years ago
Please I'm not getting how that 3 came please explain anyone?
C.h.udhay said:
9 years ago
30/x - 30/2x = 3.
30/x - 15/x = 3.
15/x = 3.
15/3 = x.
5 = x.
30/x - 15/x = 3.
15/x = 3.
15/3 = x.
5 = x.
Ranjani said:
1 decade ago
@Devi, why do you subtract 30/x and 30/2x and t+2 and t-1?
Neha said:
8 years ago
Why subtraction takes place? Please, tell me the reason.
UDAY said:
8 years ago
Your method is correct and easy to understand @Devi.
Haeshal said:
8 years ago
I don't understand it. Please, someone explain it.
Urvi said:
6 years ago
Thanks, @Prakash. Understood the common factor.
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