Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
204 comments Page 4 of 21.
Joel said:
5 years ago
Without stops, Bus travels - 54 Km in 1 hr.
With stops, the bus travels- 45 Km in 1 hr.
So the extra distance the bus could have travelled if there weren't any stops= 54-45=9 Km.
So the time is taken for travelling that 9 Km is the same as the time taken for the stops,
V = d/t.
54 = 9/t.
t = 9/54 hrs=(9/54)*60=10 min.
With stops, the bus travels- 45 Km in 1 hr.
So the extra distance the bus could have travelled if there weren't any stops= 54-45=9 Km.
So the time is taken for travelling that 9 Km is the same as the time taken for the stops,
V = d/t.
54 = 9/t.
t = 9/54 hrs=(9/54)*60=10 min.
(1)
Ram said:
7 years ago
Let the distance be 270 km.
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?
PARAS FULARA said:
1 year ago
Consider the covers 54km & 45km in an hour without stoppage and with stoppage respectively. Since he covers 9 km less in stoppage.
His normal speed without stoppage is 54 km/h.
So, the time required to cover this distance is 9/54 hours i.e. 1/6 hour or 10 minutes.
So, he waited for 10 minutes in stoppage.
His normal speed without stoppage is 54 km/h.
So, the time required to cover this distance is 9/54 hours i.e. 1/6 hour or 10 minutes.
So, he waited for 10 minutes in stoppage.
(15)
Jason Valentine said:
1 year ago
Speed of bus ->54 km/ hr(without stopping the bus)
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T = 9/54.
T = 1/6 hr.
( 1 hr -> 60 min).
T = 1/6 *60min.
T = 10 min.
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T = 9/54.
T = 1/6 hr.
( 1 hr -> 60 min).
T = 1/6 *60min.
T = 10 min.
(22)
Kaviprema k said:
1 year ago
Speed of bus ->54 km/ hr(without stopping the bus)
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T= 9/54.
T= 1/6 hr.
( 1 hr -> 60 min).
T= 1/6 *60min.
T= 10 min.
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T= 9/54.
T= 1/6 hr.
( 1 hr -> 60 min).
T= 1/6 *60min.
T= 10 min.
(15)
Rukshana said:
1 decade ago
Rahul....Question is right only...Actually without stoppages it cover 54 but with stoppages it cover only 45...so only we need to subtract...to get the speed without stoppages..so 54-45=9..Then we having speed with stoppages ..so only considering 9\54 then we need to get min so mul by 60..now got?
Pratik said:
1 decade ago
Let us suppose 10 min is the ans..
Let the distance covered be 54km.
Time 1 hr without stoppage.
Then 54/1 = 54 kph..
With stoppage of 10 min= 1/6 hr= 0.1667 hr
54/(1+0.1667)= 46.28 kph
---------------------------------
Let 12 min be the ans
With stoppage 0f 12 min=1/5hr=0.2hr
54/(1+0.2)= 45 kph.
Let the distance covered be 54km.
Time 1 hr without stoppage.
Then 54/1 = 54 kph..
With stoppage of 10 min= 1/6 hr= 0.1667 hr
54/(1+0.1667)= 46.28 kph
---------------------------------
Let 12 min be the ans
With stoppage 0f 12 min=1/5hr=0.2hr
54/(1+0.2)= 45 kph.
KArthik said:
6 years ago
Hey guys, for this we can simply use the proportion method;
60min : 54km :: x min : 9km (product of extremes = product of means)
60*9=54x.
x=(60*9)/54 (9 and 54 will be cancelled by 9 tables)
x=60/6 (60 and 6 will be cancelled by 6 tables)
x=10min.
Therefore, the time taken by train is 10 min.
60min : 54km :: x min : 9km (product of extremes = product of means)
60*9=54x.
x=(60*9)/54 (9 and 54 will be cancelled by 9 tables)
x=60/6 (60 and 6 will be cancelled by 6 tables)
x=10min.
Therefore, the time taken by train is 10 min.
Ramesh said:
4 years ago
Let's we take that a bus reach an 54 km distance in 1 hour without any stoppages while the bus was covered 45 distance with some stop.
So we can understand that the remaining 9 kms were not reached the bus.
So, 9 km travelling time will be a stop time. We all know that, time=9/54*60=10 mins.
So we can understand that the remaining 9 kms were not reached the bus.
So, 9 km travelling time will be a stop time. We all know that, time=9/54*60=10 mins.
(5)
Yen said:
2 years ago
@All.
Here is my solution;
For me, in 1 hour the bus runs 54 km by the speed of 54km/h excluding stops.
But because of stop time, it runs by a speed 45km/h.
That means 54 km/ times = 45 ( km/h).
So the total times needed is 54/45 = 6/5 h,
And stop time is 6/5 -1 = 1/5h = 12 minutes.
Here is my solution;
For me, in 1 hour the bus runs 54 km by the speed of 54km/h excluding stops.
But because of stop time, it runs by a speed 45km/h.
That means 54 km/ times = 45 ( km/h).
So the total times needed is 54/45 = 6/5 h,
And stop time is 6/5 -1 = 1/5h = 12 minutes.
(9)
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