Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
206 comments Page 4 of 21.
ARJUN SAHOO said:
1 decade ago
See..the bus runs up to 54 kmph in 60m. in nonstop mode.
If 45km in stop mode, the bus will take 72 minutes to travel 54 km in stop mode.(60/45*54).
So here bus taking 12 more minutes to reach at the destination but in 72 minutes. As per question, in 60 minutes the bus will take extra minutes to halt => 12/72*60=10 proved. Answer is 10.
If 45km in stop mode, the bus will take 72 minutes to travel 54 km in stop mode.(60/45*54).
So here bus taking 12 more minutes to reach at the destination but in 72 minutes. As per question, in 60 minutes the bus will take extra minutes to halt => 12/72*60=10 proved. Answer is 10.
Joel said:
5 years ago
Without stops, Bus travels - 54 Km in 1 hr.
With stops, the bus travels- 45 Km in 1 hr.
So the extra distance the bus could have travelled if there weren't any stops= 54-45=9 Km.
So the time is taken for travelling that 9 Km is the same as the time taken for the stops,
V = d/t.
54 = 9/t.
t = 9/54 hrs=(9/54)*60=10 min.
With stops, the bus travels- 45 Km in 1 hr.
So the extra distance the bus could have travelled if there weren't any stops= 54-45=9 Km.
So the time is taken for travelling that 9 Km is the same as the time taken for the stops,
V = d/t.
54 = 9/t.
t = 9/54 hrs=(9/54)*60=10 min.
(1)
Ram said:
7 years ago
Let the distance be 270 km.
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?
PARAS FULARA said:
2 years ago
Consider the covers 54km & 45km in an hour without stoppage and with stoppage respectively. Since he covers 9 km less in stoppage.
His normal speed without stoppage is 54 km/h.
So, the time required to cover this distance is 9/54 hours i.e. 1/6 hour or 10 minutes.
So, he waited for 10 minutes in stoppage.
His normal speed without stoppage is 54 km/h.
So, the time required to cover this distance is 9/54 hours i.e. 1/6 hour or 10 minutes.
So, he waited for 10 minutes in stoppage.
(15)
Jason Valentine said:
2 years ago
Speed of bus ->54 km/ hr(without stopping the bus)
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T = 9/54.
T = 1/6 hr.
( 1 hr -> 60 min).
T = 1/6 *60min.
T = 10 min.
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T = 9/54.
T = 1/6 hr.
( 1 hr -> 60 min).
T = 1/6 *60min.
T = 10 min.
(23)
Kaviprema k said:
2 years ago
Speed of bus ->54 km/ hr(without stopping the bus)
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T= 9/54.
T= 1/6 hr.
( 1 hr -> 60 min).
T= 1/6 *60min.
T= 10 min.
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T= 9/54.
T= 1/6 hr.
( 1 hr -> 60 min).
T= 1/6 *60min.
T= 10 min.
(15)
Rukshana said:
1 decade ago
Rahul....Question is right only...Actually without stoppages it cover 54 but with stoppages it cover only 45...so only we need to subtract...to get the speed without stoppages..so 54-45=9..Then we having speed with stoppages ..so only considering 9\54 then we need to get min so mul by 60..now got?
Pratik said:
1 decade ago
Let us suppose 10 min is the ans..
Let the distance covered be 54km.
Time 1 hr without stoppage.
Then 54/1 = 54 kph..
With stoppage of 10 min= 1/6 hr= 0.1667 hr
54/(1+0.1667)= 46.28 kph
---------------------------------
Let 12 min be the ans
With stoppage 0f 12 min=1/5hr=0.2hr
54/(1+0.2)= 45 kph.
Let the distance covered be 54km.
Time 1 hr without stoppage.
Then 54/1 = 54 kph..
With stoppage of 10 min= 1/6 hr= 0.1667 hr
54/(1+0.1667)= 46.28 kph
---------------------------------
Let 12 min be the ans
With stoppage 0f 12 min=1/5hr=0.2hr
54/(1+0.2)= 45 kph.
KArthik said:
6 years ago
Hey guys, for this we can simply use the proportion method;
60min : 54km :: x min : 9km (product of extremes = product of means)
60*9=54x.
x=(60*9)/54 (9 and 54 will be cancelled by 9 tables)
x=60/6 (60 and 6 will be cancelled by 6 tables)
x=10min.
Therefore, the time taken by train is 10 min.
60min : 54km :: x min : 9km (product of extremes = product of means)
60*9=54x.
x=(60*9)/54 (9 and 54 will be cancelled by 9 tables)
x=60/6 (60 and 6 will be cancelled by 6 tables)
x=10min.
Therefore, the time taken by train is 10 min.
Ramesh said:
4 years ago
Let's we take that a bus reach an 54 km distance in 1 hour without any stoppages while the bus was covered 45 distance with some stop.
So we can understand that the remaining 9 kms were not reached the bus.
So, 9 km travelling time will be a stop time. We all know that, time=9/54*60=10 mins.
So we can understand that the remaining 9 kms were not reached the bus.
So, 9 km travelling time will be a stop time. We all know that, time=9/54*60=10 mins.
(5)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers