Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
9
10
12
20
Answer: Option
Explanation:

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km = 9 x 60 min = 10 min.
54

Discussion:
204 comments Page 20 of 21.

Bantu Venkatesh said:   6 years ago
54km ------------- 60min
45km ------------- ?????.

45/54*60min = 50min.
60min - 50min = 10min.

KArthik said:   6 years ago
Hey guys, for this we can simply use the proportion method;
60min : 54km :: x min : 9km (product of extremes = product of means)
60*9=54x.

x=(60*9)/54 (9 and 54 will be cancelled by 9 tables)
x=60/6 (60 and 6 will be cancelled by 6 tables)
x=10min.

Therefore, the time taken by train is 10 min.

KArthik said:   6 years ago
Thank you @Kushal.

Anvi said:   5 years ago
Can anyone tell me the easy method.

Bhavya said:   5 years ago
2 speeds difference is 9 km,
So we should calculate the time taken to cover 9 km.
So, 9/54*60 =?
Then the answer is 10 minutes.

Sravani said:   5 years ago
You were excellent! Thanks, @Jaya and @Kushal.

Kumar said:   5 years ago
I didn't understand, I'm confused about this stoppages can anyone explain in detail?

Chandu said:   5 years ago
Stoppage time = difference of speed/maximum speed.
= 54-45/54 * 60min,
= 9/54 * 60min,
= 1/6 * 60min.
= 10min.

Boss said:   5 years ago
Good explanation, thanks @Jaya.

Sangay wangdi said:   5 years ago
54 km in 60 minutes.

9km in x.
Cross multiply.
60 * 9 =540/54.
Is equal to 10 minutes.
So, 9km is taking 10 minutes to stop.


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