Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
208 comments Page 18 of 21.
Raj said:
8 years ago
Thank you @Kunal.
Lohith said:
8 years ago
We can do this simply by ratios.
Given speeds 54kmph,45kmph ratio:54:45,
Speeds ratio- 6:5.
Times ratio will be- 5:6 (since speed and time are inversely proportional).
In times ratio 1 part difference is there hence in total 6 parts 1 part is stoppage we calculate (1/6)*60=10.
Given speeds 54kmph,45kmph ratio:54:45,
Speeds ratio- 6:5.
Times ratio will be- 5:6 (since speed and time are inversely proportional).
In times ratio 1 part difference is there hence in total 6 parts 1 part is stoppage we calculate (1/6)*60=10.
Priya said:
8 years ago
Thank you @Lohith.
ACHYUT KUMAR PATRA said:
8 years ago
I think 10 is the right answer. I agree with the given answer.
Naidu said:
8 years ago
Well said @Bipana.
RAJU said:
7 years ago
Bus can cover distance without stops for 60mins(60 * 54) = 3240m.
Bus can cover distance with stops for 60mins (60 * 45) = 2700m.
difference distance = 540m.
Time = distance/speed = 540/54 = 10mins.
Bus can cover distance with stops for 60mins (60 * 45) = 2700m.
difference distance = 540m.
Time = distance/speed = 540/54 = 10mins.
Borade vikas said:
7 years ago
How we take the ratio of (9÷54)*60?
Please explain this step.
Please explain this step.
Sahil said:
7 years ago
Let 54 km and 45 km is a distance that travelled by bus in *1hour*.
45 km distances travelled by car in 1 hour due to the stoppage.
If it travels without a stoppage, it would cover in a 45km/ 54kmph = 5/6h.
5*60/6 = 50 min,
60-50 = 10 minutes.
45 km distances travelled by car in 1 hour due to the stoppage.
If it travels without a stoppage, it would cover in a 45km/ 54kmph = 5/6h.
5*60/6 = 50 min,
60-50 = 10 minutes.
Ram said:
7 years ago
Let the distance be 270 km.
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?
Karthik said:
7 years ago
Simply, the solution is;
60min --> 54km
x min --> 45
>>x=50;
This means with stoppages it is taking 50 min to reach 45km.
but now without stoppage it is taking 60 min so with stoppage it is taking extra 10 min.
60min --> 54km
x min --> 45
>>x=50;
This means with stoppages it is taking 50 min to reach 45km.
but now without stoppage it is taking 60 min so with stoppage it is taking extra 10 min.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers