Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = | ![]() |
9 | x 60 | min |
= 10 min. |
| 54 |
Discussion:
206 comments Page 14 of 21.
Omega said:
9 years ago
@Sundar,
Can you explain in an easy way?
Can you explain in an easy way?
Veda said:
9 years ago
Given in the question to find out the number of minutes the bus stops per every hour.
So let us consider that the bus travels for 1 hr. The distance travelled without stopping = 1 * 54 = 54 kms.
Let the bus stops for x mins in 1 hr. So the 54 kms are covered in 1 + (x/60) hrs (converting x mins to hrs).
So, 54 = 45 * (1 + (x/60) ) => x = 12. Now the total time taken = 1 hr + 12 min = 72 min.
This means that the bus stops for 12 min in every 72 mins. We have to calculate the time the bus stops in 60 mins.
So, (12 * 60) / 72 = 10 mins.
So let us consider that the bus travels for 1 hr. The distance travelled without stopping = 1 * 54 = 54 kms.
Let the bus stops for x mins in 1 hr. So the 54 kms are covered in 1 + (x/60) hrs (converting x mins to hrs).
So, 54 = 45 * (1 + (x/60) ) => x = 12. Now the total time taken = 1 hr + 12 min = 72 min.
This means that the bus stops for 12 min in every 72 mins. We have to calculate the time the bus stops in 60 mins.
So, (12 * 60) / 72 = 10 mins.
Gangadhar said:
9 years ago
Bus A travels 54km in 60 min that means to travel 1km it takes(60/54) 1.11min.
Bus B travels 45km in 60min with stoppages.
Here, the speed of both the buses are same but bus B gives stoppages that's it.
i.e. both A & B bus covers 1 km in 1.11min only. So if bus B takes 1.11min to travel 1km then to cover 45km it will take 45 * 1.11 = 50min(actually travelled time without stoppages ).
So, the time T = travelled time with stoppages - travelled time without stoppages.
T = 60 - 50 = 10 mins.
Bus B travels 45km in 60min with stoppages.
Here, the speed of both the buses are same but bus B gives stoppages that's it.
i.e. both A & B bus covers 1 km in 1.11min only. So if bus B takes 1.11min to travel 1km then to cover 45km it will take 45 * 1.11 = 50min(actually travelled time without stoppages ).
So, the time T = travelled time with stoppages - travelled time without stoppages.
T = 60 - 50 = 10 mins.
Suyash More said:
9 years ago
Here distance is constant.
Let x be the time for which the vehicle speed.
Hence, 54 * (60 - x) = 45 * (60).......(s1 * t1= s2 * t2).
x = 10 min is the answer.
Let x be the time for which the vehicle speed.
Hence, 54 * (60 - x) = 45 * (60).......(s1 * t1= s2 * t2).
x = 10 min is the answer.
Ravi said:
9 years ago
Can anyone explain it clearly, please?
MMMMM said:
9 years ago
The speed of a train is 80 kmph and for every bogie added, the speed decreases by 10%. How many minimum numbers of bogies should be added to reduce the speed of the train to less than 50 km/h?
Can anyone tell me the answer?
Can anyone tell me the answer?
Madan said:
9 years ago
Explanation:
Excluding stoppages (ES) - 54.
Including stoppages (IS) - 45.
Formula: (ES - IS)/ ES.
=> (54 - 45)/54 = 9/54 = 1/6 hrs (or) 10 mins.
Excluding stoppages (ES) - 54.
Including stoppages (IS) - 45.
Formula: (ES - IS)/ ES.
=> (54 - 45)/54 = 9/54 = 1/6 hrs (or) 10 mins.
Md.Tamheed Khan said:
9 years ago
Nice explained @Jaya and @Kaushal.
Kathleena said:
9 years ago
Car travels with an average speed of 70 km/hr from Magallanes interchange to bicutan in 5 mi how far are these two places? How fast is the car travelling after 2 mi?
Please sole this.
Please sole this.
Manish Pillai said:
9 years ago
This can be done using allegations easily.
54 0
45
45 : 9
That is 5:1.
So, it should not travel for 1/6 of an hour that is 10 min.
54 0
45
45 : 9
That is 5:1.
So, it should not travel for 1/6 of an hour that is 10 min.
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