Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = | ![]() |
9 | x 60 | ![]() |
= 10 min. |
54 |
Discussion:
205 comments Page 11 of 21.
Mir Rokon Uddin said:
9 years ago
His regular speed reduce 54k/h to 45k/h.
So we have to find out the missing time from the regular speed.
The difference of the distance is 9kmh.
So missing time = (1* 9/54) * 60min.
= 10min.
So we have to find out the missing time from the regular speed.
The difference of the distance is 9kmh.
So missing time = (1* 9/54) * 60min.
= 10min.
Shri said:
9 years ago
@Mmmmm.
5 bogies should be added.
5 bogies should be added.
Jadhav said:
8 years ago
It's very simple.
54 - 45\54 * 60 = 10 min.
54 - 45\54 * 60 = 10 min.
Sambath said:
8 years ago
Super explanation @Jaya, @Kusal.
Rajesh.r.kzm said:
8 years ago
Excellent explanation @Jaya.
Yamine said:
8 years ago
Good explanation @Jadhav.
Bhavi said:
8 years ago
Great explanation @Kushal.
Shunail ali said:
8 years ago
Great explanation @Kushal and @Jaya.
Jayawant said:
8 years ago
Speeds given : without stoppage 54km/hr and with stoppage 45km/hr.
Vehicle has to cover same distance.
Let us assume it travels distance 270 kms (LCM of 54 and 45).
With 54 km/ hr, total 5 hrs are needed and with 45 km/hr, total 6 hrs are needed.
It means with stoppage it has to stop for I hr in 6 hrs.
So, within 1hr, it has to stop for 1/ 6 hr i.e. 10 minutes.
Vehicle has to cover same distance.
Let us assume it travels distance 270 kms (LCM of 54 and 45).
With 54 km/ hr, total 5 hrs are needed and with 45 km/hr, total 6 hrs are needed.
It means with stoppage it has to stop for I hr in 6 hrs.
So, within 1hr, it has to stop for 1/ 6 hr i.e. 10 minutes.
Palash said:
8 years ago
Great explanation @Jayawant.
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