Aptitude - Time and Distance - Discussion

The speed of the train: speed of the car = 150 : 100 = 3 : 2.
From the formula ; ratio of the speed = a:b,
if the same distance then, ratio of the time = b : a
Time ratio = 2:3
1u = 12.5 min
2u = 25 min
3u = 37.5 min.

The time taken by the car in hr = 37.5/60 = 375/600,
= 5/8 hr.
SPEED OF THE CAR IS = 75 divided by 5/8.
= 15 * 8.
= 120 km /hr.

Both reach same time but suppose TI but train losses 12.5 so train time is TI-12.5 and car time is TI.

Now WKT time=distance/speed, x be the speed of car and 3x/2 speed of the train, both distance is same.

Substitue in formula for train time=TI-12.5 dis=75 speed 3x/2 we get (TI-12.5)=75/3x/2
for car time=TI speed=x dis=75 we get TI=75/x now substitue TI In above trian equation we get;

75/x-12.5 = 75 * 2/3x convert time into 12.5/60 and the result:120km/hr

Distance between A and B = 75kms.
Let 'x' be the speed of the car.

Given that the train can travel 50% faster than the car i.e.,
Car speed = x.
Train speed = x+x*50/100 = 3/2*x.
Distance = speed*time.

Tc(Time of the car) = 75/x.
Tt(Time of the train) = 75/(3/2*x)+12.5 min(while stopping at the station).
=>75/(3/2*x)+12.5/60(into hours).
=>75/x=75/(3/2*x)+12.5/60.

By solving x = 120kmph.

We need to convert 12.5 min to hours because the options given are in kmph (kilometre per hour).

To convert 12.5 min to hours you divide it by 60.

To make calculation easier 12.5 is converted into 125 by multiplying it by 10. If you multiply numerator with a number, then you also have to multiply denominator by that number.

Hence in this case it will be 12.5*10/60*10 = 125/600 which is actually the same as 12.5/60.

125/600 = 5/24.

12.5/60 = 5/24.

If the car speed is 100kmph then the train speed is 150 kmph.
Because train 50% extra speed than a car.

Train in station stopping time is 12.5min.
But a car and train cover the same distance.
In case the train running non-stoping train cover more distance.
car: train 100%:150%.
car : train 100% ====(100% + 12.5min)

That 50% is 12.5min.
100% = 2 * 12.5min.
100% = 25min..
37.5min =75kmph
1min = 75/37.5
1min = 2 kmph
1hour = 60min = 2 * 60 = 120kmph.

Friends......

let speed of car be x
thus, speed of train (150/100)x (stated that train is 50% faster than car)

now since the train lost 12.5 mins. i.e. the difference between time taken by car and time taken by train is 12.5 mins,

and since TIME=DISTANCE/SPEED

time taken by car= 75/x
time taken by train= 75/(150/100)x or 75/(3/2)x

and the difference between time taken by car and time taken by train is 75/x - 75/(3/2)x = 125/10*60.

x=120 kmph

Let Car's speed be x Kmph
Train speed = (Carspeed + (50*Carspeed)/100)
" = (x+(50x)/100)
" = 150x/100
" = 3/2xKmph

Now the train lost about 12.5min, so time subtraction betn Car and train will give us distance covered by car in that much period of time (lost period)and to know the speed we have to equate it with lost period
Distance covered = lostPeriod
75/x-75/(3/2)x = 125/600
75/x-50/x = 5/24
x = (25*24/5)=120 Kmph.

A to B=75 km.

Distance T = Time.

S = Speed, D = Distance.

Let S of car = x kmph.

S of train = 50% of car speed = x+{(50/100)*x}.

= x+{(1/2)*x}.
= x+x/2 = 3x/2.

T = D/S.

T of car - T of train = 12.5 mins as car speed is low that of train speed.

= 75/x-75/(3x/2) = 12.5/60 (converting 12.5 mins to 12.5/60 hr).
= 75/x-75*2/3x = 12.5/60.

= 75/x-50/x = 12.5/60.
= 25/x = 12.5/60.

x = 25*60/12.5 = 25*60*10/125 = 120.
x = 120 kmph.

Let speed of car be = x km/hr.

Then, speed of train will be = 50% more than car.

50% means half of speed of car.

Half of car speed can be written as "x/2.

Then, speed of train will be = x+x/2 = 3x/2.

Total distance = 75km.

Then, according to question Time = Distance/Speed,

75/3x/2-75/x = 12.5.
300/3x-75/x = 125/10/60.
300-225/3x = 125/600.

75/3x = 5/24.
3x*5 = 75*24.
3x = 75*24/5.

Therefore, x = 75*24/15.

x = 5*24 = 120.

The car and train reached 75km at the same time.the train was late for 12.5 mins.
The train could reach 12.5 mins faster than the car.
* 75/x is the timing of car to reach 75kms.
*75/(3x/2) +12.5/60(time for stops) is the time taken by train to reach 75kms.
*Both the timings are equal since the time taken by both car and train are equal so then you can get the equation.
75/x = 75/(3x/2) + 12.5/60.
75/x - 75/(3x/2) = 12.5/60.