Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
Then, speed of the train = | 150 | x | = | ![]() |
3 | x | ![]() |
100 | 2 |
![]() |
75 | - | 75 | = | 125 |
x | (3/2)x | 10 x 60 |
![]() |
75 | - | 50 | = | 5 |
x | x | 24 |
![]() |
![]() |
25 x24 | ![]() |
= 120 kmph. |
5 |
Discussion:
345 comments Page 33 of 35.
Bhu said:
1 decade ago
Time of train+12.5 = Time of car.
Pallavi said:
10 years ago
Can you explain from second step?
Sanju said:
8 years ago
Good explanation, thanks @Raihan.
Kalyan said:
5 years ago
Can you explain how 150/100 came?
Shivam said:
4 years ago
Thanks for explaining the answer.
Ramesh said:
1 decade ago
Why the LHS is equated with RHS?
Asawari said:
7 years ago
Anyone explain me from 2nd step.
Rajeev said:
9 years ago
Actually, here x = (25 x 15)/5?
Sachin said:
1 decade ago
And what about that 12.5 min?
Vipul said:
1 decade ago
Can you explain how 125/10*6?
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