Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
Then, speed of the train = | 150 | x | = | ![]() |
3 | x | ![]() |
100 | 2 |
![]() |
75 | - | 75 | = | 125 |
x | (3/2)x | 10 x 60 |
![]() |
75 | - | 50 | = | 5 |
x | x | 24 |
![]() |
![]() |
25 x24 | ![]() |
= 120 kmph. |
5 |
Discussion:
342 comments Page 31 of 35.
ANAND said:
1 decade ago
50% car faster means 100%+50% = 150.
SHOBA said:
9 years ago
Can you explain about 12.5*10/60*10?
Tesit said:
9 years ago
Can you explain, how 125/ (10 * 60)?
Pradeep said:
1 decade ago
Can you exlpain how 150x/100 came ?
Maheshwaran said:
1 decade ago
HOW 150 comes in the initial step ?
Rakshak said:
9 years ago
Can you explain, how 125/(10 * 60)?
Ravikumar J said:
8 years ago
Good explanation, thank you @Rihan.
Arvindra shukla said:
8 years ago
How come 125 and why divided by 60?
Arvind said:
4 years ago
T = D/S
T = 75/X-75/1.5X = 12.5/60.
T = 75/X-75/1.5X = 12.5/60.
Caroline said:
2 years ago
How 150 came? Please explain to me.
(44)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers