Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
342 comments Page 31 of 35.
Shivam said:
4 years ago
Thanks for explaining the answer.
Piyush said:
4 years ago
@All.
So many of us are confused in where the hell this (150x/100) came from right.
So, my simple explanation is that see the train is 50% faster than car.
Now, consider car speed is X so the train speed will be (X+ 50% of X) Now calculate the train speed.
And you will get (X + 50X/100) = 150X/100.
Hope this helps.
So many of us are confused in where the hell this (150x/100) came from right.
So, my simple explanation is that see the train is 50% faster than car.
Now, consider car speed is X so the train speed will be (X+ 50% of X) Now calculate the train speed.
And you will get (X + 50X/100) = 150X/100.
Hope this helps.
(9)
Ayush said:
3 years ago
Please anyone can explain since the speed of the train is 1.5 * speed of the car, so how in the solution we are taking that difference of time is 12.5 min. How we come to know that if 12.5min added to the time taken by car will equal to the time taken by train?
Since the speed of both is different so how can they have time taken by car = T and by train =T+12.5 * 60.
Since the speed of both is different so how can they have time taken by car = T and by train =T+12.5 * 60.
Tharun kumar said:
3 years ago
Let the speed of the car be x.
As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].
So, (150/100) x.
As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].
So, (150/100) x.
(1)
Naz said:
3 years ago
75/x * 1.5 = 75/x-12.5 (speed of car * 1.5 = speed pf train).
X= 37.5 time taken (min).
Car speed 75/(37.5/60) as time was in mins.
X= 37.5 time taken (min).
Car speed 75/(37.5/60) as time was in mins.
(6)
Rakesh Selvam A said:
3 years ago
By ratio of Speed.
T :C = 150: 100,
= 3:2.
Since, Distance is constant.
Time ratio = 2:3.
Diff between time ratios 2 and 3 is 1, which means 1 = 12.5 mins.
1 -----> 12.5 min,
3------> 37.5min,
2 ------> 25 min,
,
Speed of Car = Distance/Time.
= (75 /37.5) * 60( For min to hr),
= 120km/hr.
T :C = 150: 100,
= 3:2.
Since, Distance is constant.
Time ratio = 2:3.
Diff between time ratios 2 and 3 is 1, which means 1 = 12.5 mins.
1 -----> 12.5 min,
3------> 37.5min,
2 ------> 25 min,
,
Speed of Car = Distance/Time.
= (75 /37.5) * 60( For min to hr),
= 120km/hr.
(94)
Bhushan said:
3 years ago
Let the speed of car be x.
now, the train is 50% faster than a car,
i.e. speed of the train = x + (50/100)x.
= 150x/100.
now, the train is 50% faster than a car,
i.e. speed of the train = x + (50/100)x.
= 150x/100.
(16)
Charles said:
3 years ago
I did not understand. Please help me to get it.
(17)
Rohan said:
3 years ago
Someone help me in this by explaining this.
(8)
Rushi Gadi said:
3 years ago
n any of the time distance sum out of time, distance, speed one of the quantities common
Here the time is common;
So we;
d = s*t.
Car Time = train Time.
Dist of car/Speed of car = Dist of train/Speed of train.
But here is train takes extra time for pause which must be equal.
Time train = Time of train running + Time train pass.
Time train running + Time train pass = Dist of car/Speed of the car.
Time train running - Dist car/Speed car = Time train pass.
75/1.5(x) -75/x = 12.5/60.
FYI (12.5/60 = 125/10*60),
x = 120Km/hr.
Here the time is common;
So we;
d = s*t.
Car Time = train Time.
Dist of car/Speed of car = Dist of train/Speed of train.
But here is train takes extra time for pause which must be equal.
Time train = Time of train running + Time train pass.
Time train running + Time train pass = Dist of car/Speed of the car.
Time train running - Dist car/Speed car = Time train pass.
75/1.5(x) -75/x = 12.5/60.
FYI (12.5/60 = 125/10*60),
x = 120Km/hr.
(18)
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