Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
Then, speed of the train = | 150 | x | = | ![]() |
3 | x | ![]() |
100 | 2 |
![]() |
75 | - | 75 | = | 125 |
x | (3/2)x | 10 x 60 |
![]() |
75 | - | 50 | = | 5 |
x | x | 24 |
![]() |
![]() |
25 x24 | ![]() |
= 120 kmph. |
5 |
Discussion:
345 comments Page 28 of 35.
Sowmiya.k said:
1 decade ago
Please anybody explain it briefly I can't understand.
SONAI SHEIKH said:
1 decade ago
Why 10 is multiplied with 12.5? Can anybody explain?
Kamesh said:
1 decade ago
I don't understand this problem please solve easily.
Deepak said:
1 decade ago
Please explain in easy way can't understand please.
Hemant said:
1 decade ago
Explain the simple way, (75/x)-(75/(3/2)x)=12.5/60
Sankalp said:
1 decade ago
Can anyone please explain me this solution easily?
Jeeva said:
1 decade ago
I cannot understand this problem. Briefly explain.
Sharada said:
6 years ago
How can you get that 150/100? please explain that.
Shalini said:
2 decades ago
Hae even though its % it must me 50x/100 only na?
(1)
Shivu said:
1 decade ago
Can you please tell me how that 125/(10x60) came?
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