Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
100 kmph
110 kmph
120 kmph
130 kmph
Answer: Option
Explanation:

Let speed of the car be x kmph.

Then, speed of the train = 150 x = 3 x kmph.
100 2

75 - 75 = 125
x (3/2)x 10 x 60

75 - 50 = 5
x x 24

x = 25 x24 = 120 kmph.
5

Discussion:
344 comments Page 18 of 35.

Ravi kataria said:   8 years ago
As a train is much faster, then time difference must be [distance /train speed - distance /car speed =12.5min].

Then, how it does inversely?

Sagar Bhamare said:   8 years ago
The total speed of a car 100% + 50% extra,
So the speed of the train is 150%.

Which can be written as (150/100)X.

Priya said:   9 years ago
Can you exlpain how 150x/100 came?

Rajesh.r.kzm said:   9 years ago
12.5 can be taken as 125/10. So it will be multiplied by no of minutes in an hour. So, it is 125/(10*60).

Tesit said:   9 years ago
Can you explain, how 125/ (10 * 60)?

Rakshak said:   9 years ago
Can you explain, how 125/(10 * 60)?

Vishnu b nair said:   9 years ago
The speed of both of them is 100 per cent and the train is 50% more faster than car it means the train have the 100 + 50 = 150%.

Hong Kong said:   9 years ago
But can anyone explain to me why can't I think like this:

Let x be the time for Bus to arrive point B, then x = 12.5x2 (since train 50% faster) = 25.
So we know the train bus spend 25 mins to arrive B, and 75km/25mins = 3km/mins = 180kmph?

Ankit said:   9 years ago
Let me explain : assume car travel at speed x so speed of train 50% more than car 50/100 * x or 0.5 x.

So total speed of train faster than car is x + 0.5x which is 1.5x. Meaning of 150/100 * x = 1.5x.

Palani said:   9 years ago
But in question (50% more) is not given, only 50% faster is given so explain me the correct solution.


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