Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
Then, speed of the train = | 150 | x | = | ![]() |
3 | x | ![]() |
100 | 2 |
![]() |
75 | - | 75 | = | 125 |
x | (3/2)x | 10 x 60 |
![]() |
75 | - | 50 | = | 5 |
x | x | 24 |
![]() |
![]() |
25 x24 | ![]() |
= 120 kmph. |
5 |
Discussion:
345 comments Page 17 of 35.
Amit Chauhan LPU said:
9 years ago
150/100 X it came because.
50% more than X ie :
=> (50/100) * x + x.
==> 150/100 * x.
50% more than X ie :
=> (50/100) * x + x.
==> 150/100 * x.
Gowtham Sunny said:
9 years ago
Here, Train and car reach at the same time.
So, T1(Car) = T2(train).
Then, T1(Car) = T2(train) + 12.5
So, T1 - T2 = 12.5.
Given Distance = 75,
Let speed be x.
Speed = x -----> Car speed.
Speed = x + 50/100 of x = 3x/2 -----> Train speed.
Therefore, T1 - T2 = 12.5.
75/x - 75/(3x/2) = 12.5 min.
(75 - 150)/x = 12.5/60 hr (Since we are cal in kmph we should convert min to hrs).
x = 120 kmph.
So, T1(Car) = T2(train).
Then, T1(Car) = T2(train) + 12.5
So, T1 - T2 = 12.5.
Given Distance = 75,
Let speed be x.
Speed = x -----> Car speed.
Speed = x + 50/100 of x = 3x/2 -----> Train speed.
Therefore, T1 - T2 = 12.5.
75/x - 75/(3x/2) = 12.5 min.
(75 - 150)/x = 12.5/60 hr (Since we are cal in kmph we should convert min to hrs).
x = 120 kmph.
Anonymous said:
9 years ago
Thank u@Prawinn.
Dip said:
9 years ago
Please anyone can explain me how 125/600 came?
Palani said:
9 years ago
But in question (50% more) is not given, only 50% faster is given so explain me the correct solution.
Ankit said:
9 years ago
Let me explain : assume car travel at speed x so speed of train 50% more than car 50/100 * x or 0.5 x.
So total speed of train faster than car is x + 0.5x which is 1.5x. Meaning of 150/100 * x = 1.5x.
So total speed of train faster than car is x + 0.5x which is 1.5x. Meaning of 150/100 * x = 1.5x.
Hong Kong said:
9 years ago
But can anyone explain to me why can't I think like this:
Let x be the time for Bus to arrive point B, then x = 12.5x2 (since train 50% faster) = 25.
So we know the train bus spend 25 mins to arrive B, and 75km/25mins = 3km/mins = 180kmph?
Let x be the time for Bus to arrive point B, then x = 12.5x2 (since train 50% faster) = 25.
So we know the train bus spend 25 mins to arrive B, and 75km/25mins = 3km/mins = 180kmph?
Vishnu b nair said:
9 years ago
The speed of both of them is 100 per cent and the train is 50% more faster than car it means the train have the 100 + 50 = 150%.
Rakshak said:
9 years ago
Can you explain, how 125/(10 * 60)?
Tesit said:
9 years ago
Can you explain, how 125/ (10 * 60)?
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