Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
355 comments Page 11 of 36.
Jyothi said:
8 years ago
Here we take 150/100 because it is given 50% more and always we have to take 100 as a base value here it is 50%more so 100+50/100 = 150/100 = 3/2.
(If it is given less than 50% then 100-50/100 = 50/100 = 1/2.
I hope you all understand.
(If it is given less than 50% then 100-50/100 = 50/100 = 1/2.
I hope you all understand.
PALAK said:
5 years ago
Let the car speed be x.
Speed of train = 150/100x = 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x = 25*24/5.
x = 5*24.
x = 120.
Speed of train = 150/100x = 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x = 25*24/5.
x = 5*24.
x = 120.
(1)
Ashish Katoch said:
1 decade ago
150/100 come using this strategy.
<-------------simple logic:------------->
Suppose car speed =x km/hr.
Then train speed= x + 0.5x.
1.5x or 150/100 or 3/2.
{0.5x comes by breaking the 1x into half (50%) i.e 1/2 i.e 0.5}.
<-------------simple logic:------------->
Suppose car speed =x km/hr.
Then train speed= x + 0.5x.
1.5x or 150/100 or 3/2.
{0.5x comes by breaking the 1x into half (50%) i.e 1/2 i.e 0.5}.
MikesMatE said:
9 years ago
@ALL.
150x/100 is to say that if the car travelled at x speed which is 100%x=x, then the train was 50% faster than that, 2x is an addition of 100% to x not 50%.
Therefore to add 50% to x would be to add 1/2x which makes it 3/2x.
150x/100 is to say that if the car travelled at x speed which is 100%x=x, then the train was 50% faster than that, 2x is an addition of 100% to x not 50%.
Therefore to add 50% to x would be to add 1/2x which makes it 3/2x.
Hemant Sharma said:
2 decades ago
Hi, its right, I'm little confuse that why calculate difference b/w both but car lost time 12.5.so the difference b/w boths time is equal to the lost time | i.e 12.5 is equal to the 125/10 and change into hrs so 125/(60*10) .
Prawinn said:
2 decades ago
Simple train and car reach the place in a same time if car takes 8 hours to reach the place train also take 8 hours that 8 hour be t+somewaste of time the diff b/w both train and car is 0.
So, t1-(t+x) = 0
=> t1-t = x .
So, t1-(t+x) = 0
=> t1-t = x .
ABHISHEK said:
1 year ago
The speed of car be x km/h.
Then speed of the train will be = 3x/2km/h,
and the time taken to cover up 75 km is equal, but the train lost about 12.5 minutes while stopping at the stations.
So 75/x - 50/x = 5/24,
x= 120km/h.
Then speed of the train will be = 3x/2km/h,
and the time taken to cover up 75 km is equal, but the train lost about 12.5 minutes while stopping at the stations.
So 75/x - 50/x = 5/24,
x= 120km/h.
(4)
Adla said:
6 years ago
Car speed is x.
Speed of train = 150/100x= 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x= 25*24/5.
x= 5*24.
x= 120.
Speed of train = 150/100x= 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x= 25*24/5.
x= 5*24.
x= 120.
Soham said:
9 years ago
Many have asked how 3/2x came?
According to me "train travels 50% faster than car"
Let the speed of car be x.
Then the speed of train is,
The speed of car+ 50%speed of car (as per question)
ie,
x+ 1/2x.
=3/2x.
According to me "train travels 50% faster than car"
Let the speed of car be x.
Then the speed of train is,
The speed of car+ 50%speed of car (as per question)
ie,
x+ 1/2x.
=3/2x.
Ratul said:
8 years ago
Actually, it is time of car to cover the required distance and train take same time but including 12.5 minutes.
So both take same time you can rearrange the formula to understand easily.
(75/x) = (12.5/60)+-(75/(3/2)x).
So both take same time you can rearrange the formula to understand easily.
(75/x) = (12.5/60)+-(75/(3/2)x).
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers