Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
342 comments Page 11 of 35.
Adla said:
5 years ago
Car speed is x.
Speed of train = 150/100x= 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x= 25*24/5.
x= 5*24.
x= 120.
Speed of train = 150/100x= 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x= 25*24/5.
x= 5*24.
x= 120.
Soham said:
8 years ago
Many have asked how 3/2x came?
According to me "train travels 50% faster than car"
Let the speed of car be x.
Then the speed of train is,
The speed of car+ 50%speed of car (as per question)
ie,
x+ 1/2x.
=3/2x.
According to me "train travels 50% faster than car"
Let the speed of car be x.
Then the speed of train is,
The speed of car+ 50%speed of car (as per question)
ie,
x+ 1/2x.
=3/2x.
Ratul said:
7 years ago
Actually, it is time of car to cover the required distance and train take same time but including 12.5 minutes.
So both take same time you can rearrange the formula to understand easily.
(75/x) = (12.5/60)+-(75/(3/2)x).
So both take same time you can rearrange the formula to understand easily.
(75/x) = (12.5/60)+-(75/(3/2)x).
Ajit said:
1 decade ago
In given problem ,u ve to equate total or exact time of both...
Let t be time tkn by car to cover 75kms... n t' be time takn by train...
i.e. train's total time=stoppage time+time in which it covers 75kms...nw t=t'....
Let t be time tkn by car to cover 75kms... n t' be time takn by train...
i.e. train's total time=stoppage time+time in which it covers 75kms...nw t=t'....
Yogi said:
4 years ago
The Speed of train increase by 1/2, means time reduce by 1/3, this 1/3 time reduction is 12.5 minute.
So, 1/3 = 12.5/37.5.
Means the car will take three-time of 12.5 minutes which 37.5 minutes.
75 x 60/37.5 = 120kmph.
So, 1/3 = 12.5/37.5.
Means the car will take three-time of 12.5 minutes which 37.5 minutes.
75 x 60/37.5 = 120kmph.
(1)
Loganayaki said:
8 years ago
Car speed is X , and train speed is 50percent faster. Therefore train speed is,
=>car's speed + 50percent of car's speed.
=> x + (50*x)/100,
=>(100x+50x)/100,
=> 150x/100,
=>3x/2 is the speed of train.
=>car's speed + 50percent of car's speed.
=> x + (50*x)/100,
=>(100x+50x)/100,
=> 150x/100,
=>3x/2 is the speed of train.
Anas said:
6 years ago
Both trains start at the same time and reach the destination at the same time. So the time taken by both trains should be the same right? So the difference between the times should be zero. How come it is 125/10*60?
K. srinivasan said:
1 decade ago
Let the speed of the car be 10km/h and so as the speed of the train is 50% more ie 50% of 10 is 5 and so the speed of the train can be assumed to be 15km/h. Based on this assumption also this problem can be solved.
Abraham said:
6 years ago
Speed of car be x.
Speed of train= x+x/2 = 3x/2 ie; 1.5x.
Train didnt run for 12.5min ie; 12.5/60 hrs.
Difference between time ran by both is 12.5/60hr.
ie: (75/x) - (75/1.5x) = 12.5/60.
Upon solving x= 120kmph.
Speed of train= x+x/2 = 3x/2 ie; 1.5x.
Train didnt run for 12.5min ie; 12.5/60 hrs.
Difference between time ran by both is 12.5/60hr.
ie: (75/x) - (75/1.5x) = 12.5/60.
Upon solving x= 120kmph.
Bindu sree said:
2 years ago
The speed of train and car = 150 : 100 = 3 : 2.
Speed = 1/time,
Time = 2 : 3.
Delay = 12.5 for train,
So, car time = train delay × 3 = 3 × 12.5 = 37.5min = 37.5/60 = 5/8h.
Finally speed = d/t =75/5/8 =120km/h.
Speed = 1/time,
Time = 2 : 3.
Delay = 12.5 for train,
So, car time = train delay × 3 = 3 × 12.5 = 37.5min = 37.5/60 = 5/8h.
Finally speed = d/t =75/5/8 =120km/h.
(127)
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