Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 15)
15.
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Answer: Option
Explanation:
Let distance = x km and usual rate = y kmph.
| Then, | x | - | x | = | 40 |  2y(y + 3) = 9x ....(i) |
| y | y + 3 | 60 |
| And, | x | - | x | = | 40 | y(y - 2) = 3x ....(ii) |
| y -2 | y | 60 |
On dividing (i) by (ii), we get: x = 40.
Discussion:
118 comments Page 6 of 12.
Durgesh Singh said:
6 years ago
S + s1/s1*t1=S+s2/s2*t2=T.
So S+3/3*40=S-2/2*40,
S= 12.
Then T= 12+3/3*40/60 = 10/3.
ST = D.
So 10/3*12 = 40.
So S+3/3*40=S-2/2*40,
S= 12.
Then T= 12+3/3*40/60 = 10/3.
ST = D.
So 10/3*12 = 40.
Sonu kumar said:
8 years ago
@Akash.
I can't understand why have you divided by e3 and 2 on both side of equations. Can you explain please?
I can't understand why have you divided by e3 and 2 on both side of equations. Can you explain please?
Shaju said:
1 decade ago
After getting y=12, put the value of y in X/y - X/y+3 = 40/60
Then you will get X=40 without any minus sign.
Then you will get X=40 without any minus sign.
Rajasekhar said:
6 years ago
d=(S1S2/S1-S2)*t.
(S(S+3) / 3)*(40/60)=(S(S-2)/2)*(40/60).
2S+6= 3S-6.
S=12Kmph.
d=( (12*15)/3)*40/60.
d=40km.
(S(S+3) / 3)*(40/60)=(S(S-2)/2)*(40/60).
2S+6= 3S-6.
S=12Kmph.
d=( (12*15)/3)*40/60.
d=40km.
(4)
Ramakrishna said:
10 years ago
@Sivaram,
Here 3 is kmhr, but 40 is minutes.
Our requirement is Distance in KM.
So Please explain clearly?
Here 3 is kmhr, but 40 is minutes.
Our requirement is Distance in KM.
So Please explain clearly?
Divya said:
8 years ago
@Dhivakar.
To convert 80 min into hour you divide it by 60 not multiply it. Then How did you get the answer?
To convert 80 min into hour you divide it by 60 not multiply it. Then How did you get the answer?
Sidzwozz said:
9 years ago
@Pauli.
According to my calculations, Jake has 4.5 Km/Hour. Let me know whether it's wrong or Right?
According to my calculations, Jake has 4.5 Km/Hour. Let me know whether it's wrong or Right?
Venish said:
2 decades ago
I want to know simplify method for that equations x/y - x/y+3 = 40/ 60 and x/y-2 - x/y = 40/60....
Nagurum said:
9 years ago
@Zaid.
After finding the time and I cannot find the distance value, how to solve? Please help me.
After finding the time and I cannot find the distance value, how to solve? Please help me.
Sandjive said:
6 years ago
@Pauli.
For Jake sum.
S*t=90.....1.
(S+15)(t-30/60)=90.......2.
Solving 2 eqn, answer: 45km/hr.
For Jake sum.
S*t=90.....1.
(S+15)(t-30/60)=90.......2.
Solving 2 eqn, answer: 45km/hr.
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