Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 15)
15.
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Answer: Option
Explanation:
Let distance = x km and usual rate = y kmph.
| Then, | x | - | x | = | 40 |  2y(y + 3) = 9x ....(i) |
| y | y + 3 | 60 |
| And, | x | - | x | = | 40 | y(y - 2) = 3x ....(ii) |
| y -2 | y | 60 |
On dividing (i) by (ii), we get: x = 40.
Discussion:
118 comments Page 5 of 12.
Eswar said:
1 decade ago
@Shathi.
Why sivaram method is not correct way?
Speed*time=distance.
Differnce of speed and time= distance.
3*40-2*40=x.
120-80=x.
40=x.
Why sivaram method is not correct way?
Speed*time=distance.
Differnce of speed and time= distance.
3*40-2*40=x.
120-80=x.
40=x.
P.abhishek said:
7 years ago
Distance= s* t.
x= actual speed,
x +3= 40 min (faster),
x-2=40 min (slower),
d= 3 * 40= 120,
d=2*40=80,
120 -80= 40.
It's an actual answer.
x= actual speed,
x +3= 40 min (faster),
x-2=40 min (slower),
d= 3 * 40= 120,
d=2*40=80,
120 -80= 40.
It's an actual answer.
(2)
Akash said:
1 decade ago
Hello @Jiya.
x/y-2 + 40/60 = x/y+3 - 40/60.
(x/y-2)-(x/y+3) = -2/3.
y-2/x - y+3/x = -3/2.
(y-2-y-3)/x = -3/2.
-5/x = -3/2.
x = 10/3.
x/y-2 + 40/60 = x/y+3 - 40/60.
(x/y-2)-(x/y+3) = -2/3.
y-2/x - y+3/x = -3/2.
(y-2-y-3)/x = -3/2.
-5/x = -3/2.
x = 10/3.
Shalu said:
1 decade ago
After getting y=12, substitute y in any of the eqation to find out the x value, because it is considered as distance which we want to find.
PaulI said:
9 years ago
How about this question?
Had Jake traveled 15 kph faster, the 90 km trip would have taken him 30 mins earlier. What is his speed?
Had Jake traveled 15 kph faster, the 90 km trip would have taken him 30 mins earlier. What is his speed?
Fatima said:
1 decade ago
Please can anyone tell how to write these equation?
x/y - x/y+3 = 40/60.
x/y-2 - x/y = 40/40.
Please give some basic concept.
x/y - x/y+3 = 40/60.
x/y-2 - x/y = 40/40.
Please give some basic concept.
Posubabu said:
3 years ago
(a(a-2)/2) * 40 = (a(a+3)/3) *40.
a=12kmph this is original speed.
Ddistance = (12(12-10)/2)*40/60.
Distance = 40km.
a=12kmph this is original speed.
Ddistance = (12(12-10)/2)*40/60.
Distance = 40km.
(12)
Simran said:
2 decades ago
I didn't understand this solution of the above mentioned question.Could you please give a little better explanation.
(1)
Bala said:
8 years ago
Why we have to divide both equations?
Why can't do either addition or subtraction?
Let me know the reason, please.
Why can't do either addition or subtraction?
Let me know the reason, please.
Hemanth said:
7 years ago
@Amit.
Please, can you explain how to solve those 3 equations in a easy or some possible method? Please tell me.
Please, can you explain how to solve those 3 equations in a easy or some possible method? Please tell me.
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