Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 15)
15.
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Answer: Option
Explanation:
Let distance = x km and usual rate = y kmph.
| Then, | x | - | x | = | 40 |  2y(y + 3) = 9x ....(i) |
| y | y + 3 | 60 |
| And, | x | - | x | = | 40 | y(y - 2) = 3x ....(ii) |
| y -2 | y | 60 |
On dividing (i) by (ii), we get: x = 40.
Discussion:
118 comments Page 12 of 12.
Shreeshail karajol said:
7 years ago
How come 40/60? Please explain.
Kamu said:
7 years ago
Why subtracting the equation?
Gaurav sisodiya said:
6 years ago
(40*3)-(40*2),
120-80 = 40.
120-80 = 40.
(1)
Mohammed shamil said:
6 months ago
Good thanks for explaining.
(1)
Shweta said:
6 years ago
Thank you @Sachin bhagat.
Madhavi said:
7 years ago
Thanks @Amit Kr. Soni.
(1)
Md Parvez Islam said:
6 years ago
Thanks @Sachin Bhagat.
Nisha said:
6 years ago
Thanks @Sachin Bhagat.
(1)
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