Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 15)
15.
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Answer: Option
Explanation:
Let distance = x km and usual rate = y kmph.
| Then, | x | - | x | = | 40 |  2y(y + 3) = 9x ....(i) |
| y | y + 3 | 60 |
| And, | x | - | x | = | 40 | y(y - 2) = 3x ....(ii) |
| y -2 | y | 60 |
On dividing (i) by (ii), we get: x = 40.
Discussion:
121 comments Page 11 of 13.
Nive said:
1 decade ago
Still am not able to understand, its confusing !
Neeraj said:
9 years ago
3/x+3/2/x-2= 40/40.
On solving we get x = 12.
On solving we get x = 12.
Kuru said:
1 decade ago
@Teja it's much better explanation.
Thanks.
Thanks.
Anmol ratan said:
1 decade ago
X/y-2+40/60=x/y+3-40/60 is a wrong equation.
Sirisha said:
8 years ago
Thanks for your explanation @Akash Kishor.
Dewashish said:
1 decade ago
Solve the minimum value of sin^2x+cos^2x.
Ruchir said:
7 years ago
How come 40/60? Please explain in detail.
Nikita said:
1 decade ago
Amit kr. Soni, good explanation. Great.
Harjeet said:
10 years ago
@Pauli.
45.
.5 = 90/x - 90/x + 15.
45.
.5 = 90/x - 90/x + 15.
Sruthi said:
1 decade ago
How to get y=12?
Once explain it.
Once explain it.
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