Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 12)
12.
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
Answer: Option
Explanation:
Let the distance travelled by x km.
| Then, | x | - | x | = 2 |
| 10 | 15 |
3x - 2x = 60
x = 60 km.
| Time taken to travel 60 km at 10 km/hr = |  |
60 |  hrs |
= 6 hrs. |
| 10 |
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
 Required speed = |
|
60 | kmph. |
= 12 kmph. |
| 5 |
Discussion:
93 comments Page 8 of 10.
Ram sai said:
6 years ago
Thanks for the answer @Ashish.
Noorandeous said:
6 years ago
6 hours before 2 PM was not given how you added it?
Erigela vani said:
6 years ago
@Shivasai.
I think here the difference between the two times I. E12noon and 2pm is 2, and also time =d÷s, so we should take distance as "X" and speeds which they are given so x÷10-x÷15=2.
I think here the difference between the two times I. E12noon and 2pm is 2, and also time =d÷s, so we should take distance as "X" and speeds which they are given so x÷10-x÷15=2.
Vani said:
6 years ago
@Bhushan suriya.
How 5 hours will get at the last at 1:00pm?
How 5 hours will get at the last at 1:00pm?
Jethalal said:
5 years ago
@Vani.
If you want to reach at 1 P. M. Then from 8 o'clock to 1 the time comes out to be 5 hrs so we have taken 5hrs and from that we got speed.
If you want to reach at 1 P. M. Then from 8 o'clock to 1 the time comes out to be 5 hrs so we have taken 5hrs and from that we got speed.
Vinitha said:
5 years ago
As the time is in AP.
Speeds are in HP.
15kmph ---> 12 pm
X kmph ---> 1pm
10kmph ---> 2 pm.
HP = 2 * 15 * 10/15 + 10,
=300/25,
=12kmph.
Speeds are in HP.
15kmph ---> 12 pm
X kmph ---> 1pm
10kmph ---> 2 pm.
HP = 2 * 15 * 10/15 + 10,
=300/25,
=12kmph.
(1)
Revant said:
5 years ago
Clear solution. Thank you so much @Ankit.
Sania prathi said:
5 years ago
Thank you @Neha.
Ranjith said:
5 years ago
Solution:
2xy/x+y >this is a formula.
2(10)(15)/10 + 15.
300/25 = 12kmph.
2xy/x+y >this is a formula.
2(10)(15)/10 + 15.
300/25 = 12kmph.
(3)
Prerna23 said:
5 years ago
Time reached -- time taken -- Speed
2 p.m. -- t -- 10 km/hr
12 noon -- t-2 -- 15 km/hr
1 p.m. -- t-1 -- ?.
Distance is constant.
Writing in terms of time and speed, t x 10 = (t-2) x 15 which gives t = 6.
Distance is 60 km, so speed required to reach in t-1= 5 hrs i.e. at 1 p.m. is 60/5 = 12 km/hr.
2 p.m. -- t -- 10 km/hr
12 noon -- t-2 -- 15 km/hr
1 p.m. -- t-1 -- ?.
Distance is constant.
Writing in terms of time and speed, t x 10 = (t-2) x 15 which gives t = 6.
Distance is 60 km, so speed required to reach in t-1= 5 hrs i.e. at 1 p.m. is 60/5 = 12 km/hr.
(7)
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