Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 12)
12.
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
8 kmph
11 kmph
12 kmph
14 kmph
Answer: Option
Explanation:

Let the distance travelled by x km.

Then, x - x = 2
10 15

3x - 2x = 60

x = 60 km.

Time taken to travel 60 km at 10 km/hr = 60 hrs = 6 hrs.
10

So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.

Required speed = 60 kmph. = 12 kmph.
5

Discussion:
93 comments Page 5 of 10.

Abhi said:   6 years ago
How 60/5 comes, does any one please tell me?

Ishwar said:   5 years ago
Let calculate distance firs say d.

D/10-d/15=2 (he reach 12noon 2hr early).

By calculating we get d = 60km.

Let's speed is S to calculate S difference between travel at first speed rate and S rate is.
60/10-60/S=1 (because he reaches by 1 am, 1hr early).

By calculating this we get.

5S=60.
S = 12kmph.

Ram sai said:   6 years ago
Thanks for the answer @Ashish.

Noorandeous said:   6 years ago
6 hours before 2 PM was not given how you added it?

Erigela vani said:   6 years ago
@Shivasai.

I think here the difference between the two times I. E12noon and 2pm is 2, and also time =d÷s, so we should take distance as "X" and speeds which they are given so x÷10-x÷15=2.

Vani said:   6 years ago
@Bhushan suriya.

How 5 hours will get at the last at 1:00pm?

Jethalal said:   5 years ago
@Vani.

If you want to reach at 1 P. M. Then from 8 o'clock to 1 the time comes out to be 5 hrs so we have taken 5hrs and from that we got speed.

Sania prathi said:   5 years ago
Thank you @Neha.

Mano said:   1 decade ago
I agree to vishu comment. How that step came ?

Divya said:   1 decade ago
Lets try a hit and trial method :

By increasing his speed by 5 km/hr (15-10) , he is saving 2 hours (2pm-12pm) , so when he reaches at 1 pm he increased speed by 2.5 (half of 5) = 12.5, from the options 12 is closest so that must be the answer :).


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