Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 12)
12.
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
Answer: Option
Explanation:
Let the distance travelled by x km.
| Then, | x | - | x | = 2 |
| 10 | 15 |
3x - 2x = 60
x = 60 km.
| Time taken to travel 60 km at 10 km/hr = |  |
60 |  hrs |
= 6 hrs. |
| 10 |
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
 Required speed = |
|
60 | kmph. |
= 12 kmph. |
| 5 |
Discussion:
93 comments Page 10 of 10.
Pinky said:
1 decade ago
When came to know that on where we have to use this avg formula ?
Please anyone answer.
Please anyone answer.
Sidhu said:
1 decade ago
It can be solve by using 2xy/x+y.
Leelakrishna said:
1 decade ago
Since the distance traveled to be same equate d = v*t.
i.e. 10*(14-t) = 15*(12-t).
From above eq find t i.e. t = 8.
Substitute in 10*(14-8) = 60km.
So velocity = 60/5 =12kmph.
i.e. 10*(14-t) = 15*(12-t).
From above eq find t i.e. t = 8.
Substitute in 10*(14-8) = 60km.
So velocity = 60/5 =12kmph.
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