Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 9)
9.
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
Answer: Option
Explanation:
| Total time taken = |  |
160 | + | 160 |  hrs. |
= | 9 | hrs. |
| 64 | 80 | 2 |
 Average speed = |
|
320 x | 2 | km/hr |
= 71.11 km/hr. |
| 9 |
Discussion:
63 comments Page 7 of 7.
Bloci said:
12 months ago
By using Formula.
2s1s2/s1 + s2.
2 * 80 * 64/80 + 64.
10240/144,
71.11 km/hr.
2s1s2/s1 + s2.
2 * 80 * 64/80 + 64.
10240/144,
71.11 km/hr.
(9)
Balamurugan said:
8 months ago
@All.
Start 1st half 160/64 = 2.5hr
second half 160/80 = 2hr
2.5 + 2 = 4.5hr.
Speed = distance/time.
s = 160 + 160/4.5
= 320/4.5 = 71.11.
Start 1st half 160/64 = 2.5hr
second half 160/80 = 2hr
2.5 + 2 = 4.5hr.
Speed = distance/time.
s = 160 + 160/4.5
= 320/4.5 = 71.11.
(13)
BALAKRISHNAN R said:
6 months ago
For the first 160km time taken is t = d/s t = 160/64 = 2.5hr,
For the second 160km, the time taken is t=d/s t=160/80 = 2hr.
Average speed = total distance/total time taken.
= 160+160/2.5+2.
= 320/4.5.
= 71.11 km/hr.
For the second 160km, the time taken is t=d/s t=160/80 = 2hr.
Average speed = total distance/total time taken.
= 160+160/2.5+2.
= 320/4.5.
= 71.11 km/hr.
(8)
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