Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 9)
9.
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
Answer: Option
Explanation:
Total time taken = | ![]() |
160 | + | 160 | ![]() |
= | 9 | hrs. |
64 | 80 | 2 |
![]() |
![]() |
320 x | 2 | ![]() |
= 71.11 km/hr. |
9 |
Discussion:
63 comments Page 1 of 7.
Kunal Savle said:
3 years ago
We can use,
Avg= 64 + 80/2.
= 144/2.
= 72 kmph.
= 72
So, here the answer is 71.11 kmph.
Avg= 64 + 80/2.
= 144/2.
= 72 kmph.
= 72
So, here the answer is 71.11 kmph.
(46)
PARVEEN said:
4 years ago
Formula use to average speed is 2xy/x+y.
First speed is x = 64,
Second speed is y = 80.
Put the speeds values in the formula.
= 2xy/x+y.
= 2x64x80/64+80,
= 10240/144,
= 71.1111 km/hr ans.
First speed is x = 64,
Second speed is y = 80.
Put the speeds values in the formula.
= 2xy/x+y.
= 2x64x80/64+80,
= 10240/144,
= 71.1111 km/hr ans.
(40)
Prashant said:
4 years ago
For 1st 160km time taken will be =160/64 = 2.5 sec.
For 2nd 160km time taken will be = 160/80 = 2 sec.
Total time taken in journey = 2.5 + 2 = 4.5 sec.
The avg speed for 320 km will be=total distance travelled/total time.
So,, 320/4.5 = 71.11 kmph.
For 2nd 160km time taken will be = 160/80 = 2 sec.
Total time taken in journey = 2.5 + 2 = 4.5 sec.
The avg speed for 320 km will be=total distance travelled/total time.
So,, 320/4.5 = 71.11 kmph.
(34)
Haseeb said:
2 years ago
Total distançe = 160+160=320
Total time = 160/64+160/80 = 4.5 = 9/2.
Av speed = TD/TT.
= 320/9/2.
= 71.11km/h.
Total time = 160/64+160/80 = 4.5 = 9/2.
Av speed = TD/TT.
= 320/9/2.
= 71.11km/h.
(23)
Rajan gond said:
4 years ago
We can apply 2xy/x+y.
Am I right?
Am I right?
(17)
Suyog said:
4 years ago
Can we use Average = (80+64)/2?
Anyone, Please tell me.
Anyone, Please tell me.
(17)
Balamurugan said:
8 months ago
@All.
Start 1st half 160/64 = 2.5hr
second half 160/80 = 2hr
2.5 + 2 = 4.5hr.
Speed = distance/time.
s = 160 + 160/4.5
= 320/4.5 = 71.11.
Start 1st half 160/64 = 2.5hr
second half 160/80 = 2hr
2.5 + 2 = 4.5hr.
Speed = distance/time.
s = 160 + 160/4.5
= 320/4.5 = 71.11.
(13)
Bloci said:
12 months ago
By using Formula.
2s1s2/s1 + s2.
2 * 80 * 64/80 + 64.
10240/144,
71.11 km/hr.
2s1s2/s1 + s2.
2 * 80 * 64/80 + 64.
10240/144,
71.11 km/hr.
(9)
BALAKRISHNAN R said:
6 months ago
For the first 160km time taken is t = d/s t = 160/64 = 2.5hr,
For the second 160km, the time taken is t=d/s t=160/80 = 2hr.
Average speed = total distance/total time taken.
= 160+160/2.5+2.
= 320/4.5.
= 71.11 km/hr.
For the second 160km, the time taken is t=d/s t=160/80 = 2hr.
Average speed = total distance/total time taken.
= 160+160/2.5+2.
= 320/4.5.
= 71.11 km/hr.
(8)
Aby said:
12 months ago
Avg speed = TD/TT.
Total Distance (TD) = 160 + 160 = 320 km.
Total Time (TT) =160/64 + 160/80 = 9/2 hr.
Avg speed = 320 * 2/9 = 71.11km/hr.
Total Distance (TD) = 160 + 160 = 320 km.
Total Time (TT) =160/64 + 160/80 = 9/2 hr.
Avg speed = 320 * 2/9 = 71.11km/hr.
(7)
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