Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 9)
9.
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
Answer: Option
Explanation:
| Total time taken = |  |
160 | + | 160 |  hrs. |
= | 9 | hrs. |
| 64 | 80 | 2 |
 Average speed = |
|
320 x | 2 | km/hr |
= 71.11 km/hr. |
| 9 |
Discussion:
63 comments Page 6 of 7.
Samiksha said:
1 decade ago
Simply you can aplly the formula ie,
2ab/a+b
then, you will get your answer.
2ab/a+b
then, you will get your answer.
Siva said:
1 decade ago
Speed=distance/time.
A) first time: 160/64 = 2.5.
B) second time: 160/80 = 2.
a+b = 2. 5+2 = 4.5.
Average speed=320/4.5 = 71.11.
A) first time: 160/64 = 2.5.
B) second time: 160/80 = 2.
a+b = 2. 5+2 = 4.5.
Average speed=320/4.5 = 71.11.
Jeevan said:
1 decade ago
We have to use like this also,
Total distance = 320.
1st half = 160.
2nd half = 160.
1st half speed = 64km/hr.
2nd half speed = 80km/hr.
Avg speed of 320km(dist) = 2*(64*80)/64+80 = 71.11 km/hr.
Total distance = 320.
1st half = 160.
2nd half = 160.
1st half speed = 64km/hr.
2nd half speed = 80km/hr.
Avg speed of 320km(dist) = 2*(64*80)/64+80 = 71.11 km/hr.
Javid Mir said:
1 decade ago
Simple;
Average speed = 2xV1xV2/V1+V2.
Avg. Speed = 2x64x80/64+80.
Avg. Speed = 2x64x80/144.
Solving we get; avg speed = 71.1 Km/hr.
Average speed = 2xV1xV2/V1+V2.
Avg. Speed = 2x64x80/64+80.
Avg. Speed = 2x64x80/144.
Solving we get; avg speed = 71.1 Km/hr.
Sajnan said:
1 decade ago
This is simple:
First calculate 160/64 = 2.5.
Then 160/60 = 2.
=>2.5+2 = 4.5.
Then calculate 320/4.5 = 71.11.
First calculate 160/64 = 2.5.
Then 160/60 = 2.
=>2.5+2 = 4.5.
Then calculate 320/4.5 = 71.11.
Damodhar said:
1 decade ago
Average speed = (2*80*64)/(64+80) = 71.11.
Laxmi said:
9 years ago
Excellent way of clarifying the doubts.
Vengatesh said:
9 years ago
Super, Thank you all.
Roksana1 said:
9 years ago
I'm using solution in this way. Whether it is correct way let me know.
Distance 1 = 160km.
Speed 1 = 64km/hr.
Distance 2 = 160km.
Speed 2 = 80km/hr.
If average distance is 320km.
Then let assume Avg speed = x.
So,
160/64 + 160/80 = 320/x.
20/8 + 16/8 = 320/x (to make the calculation easy let shortleft handed => 20 + 16/8= 320/x numbers).
=> 36/8 = 320/x.
x = 2560/36.
x = 71.11km/hr.
Distance 1 = 160km.
Speed 1 = 64km/hr.
Distance 2 = 160km.
Speed 2 = 80km/hr.
If average distance is 320km.
Then let assume Avg speed = x.
So,
160/64 + 160/80 = 320/x.
20/8 + 16/8 = 320/x (to make the calculation easy let shortleft handed => 20 + 16/8= 320/x numbers).
=> 36/8 = 320/x.
x = 2560/36.
x = 71.11km/hr.
Gayathri said:
9 years ago
@Sundar. Your explanations always make me clear, Thanks.
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