Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 9)
9.
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
Answer: Option
Explanation:
| Total time taken = |  |
160 | + | 160 |  hrs. |
= | 9 | hrs. |
| 64 | 80 | 2 |
 Average speed = |
|
320 x | 2 | km/hr |
= 71.11 km/hr. |
| 9 |
Discussion:
64 comments Page 6 of 7.
Sugumaran said:
1 decade ago
Hai praveen and S. M.
Your method is not suitable for all cases. Please avoid this method for solving this type of questions.
Your method is not suitable for all cases. Please avoid this method for solving this type of questions.
S. M. said:
1 decade ago
Simple method :- (64+84)/2 =72
Thus on safer side,
we can go with C.) 71.11 km/hr
Thus on safer side,
we can go with C.) 71.11 km/hr
Vivek said:
1 decade ago
Hi @Jai
5/2*2/1=by cross multiplication
We have get 5+4/2=9/2
5/2*2/1=by cross multiplication
We have get 5+4/2=9/2
Prajweetha said:
1 decade ago
Hello jai,
By simplyfying 160/64 we will get 5/2, while 160/80 becomes 2/1
By taking 2 as LCM we will get 5+4/2=9/2
By simplyfying 160/64 we will get 5/2, while 160/80 becomes 2/1
By taking 2 as LCM we will get 5+4/2=9/2
Jai said:
1 decade ago
Can you explain how 9/2 hours came ?
Kapil said:
2 decades ago
Since distance is same,so
avg speed= 2xy/(x+y)
avg s= (2*64*80)/(64+80)
=71.11
avg speed= 2xy/(x+y)
avg s= (2*64*80)/(64+80)
=71.11
Prveen Bilimoga said:
2 decades ago
I have a doubt, can we do like this, the first 160 hrs is 64 km speed, and the second hr is 80, total 144. so 144/2 = to 72
Priya said:
2 decades ago
@sunder Thanks.
Renuka said:
2 decades ago
Hi Sundar, very nice explaination, thank you so much.
KOMAL said:
2 decades ago
THANKS TO SUNDER WHO GIVES A GOOD SOLUTION
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