Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 9)
9.
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
Answer: Option
Explanation:
| Total time taken = |  |
160 | + | 160 |  hrs. |
= | 9 | hrs. |
| 64 | 80 | 2 |
 Average speed = |
|
320 x | 2 | km/hr |
= 71.11 km/hr. |
| 9 |
Discussion:
63 comments Page 5 of 7.
Akshay Patel said:
6 years ago
Avg speed of x and y be x+y/2.
Then given that 64+80/2=72.
Then given that 64+80/2=72.
Gayathri said:
9 years ago
@Sundar. Your explanations always make me clear, Thanks.
Suyog said:
4 years ago
Can we use Average = (80+64)/2?
Anyone, Please tell me.
Anyone, Please tell me.
(17)
Renuka said:
1 decade ago
Hi Sundar, very nice explaination, thank you so much.
Rahul said:
7 years ago
@Sundar.
It's so difficult to cut 10240/144.
It's so difficult to cut 10240/144.
KOMAL said:
2 decades ago
THANKS TO SUNDER WHO GIVES A GOOD SOLUTION
Damodhar said:
1 decade ago
Average speed = (2*80*64)/(64+80) = 71.11.
Muklesur said:
7 years ago
2xy/x+y.
2*64*80/64 + 80.
71.111 km/h.
2*64*80/64 + 80.
71.111 km/h.
Laxmi said:
9 years ago
Excellent way of clarifying the doubts.
Aryan said:
7 years ago
How did 9/2 came? please explain me.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers